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Tanzania [10]
2 years ago
9

Using the arithmetic sequence 7 10 13 16 find the 6th term of the sequence ​

Mathematics
1 answer:
algol132 years ago
8 0
22 is the correct answer
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Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation
Bingel [31]

Answer:

27

Step-by-step explanation:

2h+11=65

2h= 65-11

2h=54

then divide both side by two to find h

5 0
3 years ago
27÷819= <br> give me the quotient for 27÷819
Dafna11 [192]

Answer:

0.03296703

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3 years ago
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snow_lady [41]

Simplify the expression.

Your answer is: 3738

3 0
3 years ago
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Please help and and explain
sineoko [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
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Can someone please explain this to me? Thanks!
Makovka662 [10]

Answer:  Choice D

\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\

==========================================================

Explanation:

Let g(t) be the antiderivative of g'(t) = \sqrt{1+t^3}. We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\

From here, we apply the derivative with respect to x to both sides. Note that the g(\pi) portion is a constant, so g'(\pi) = 0

\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\

\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\

Answer is choice D

5 0
2 years ago
Read 2 more answers
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