Answer:
2x-7
x/7
3x+5
3(x+5)
Step-by-step explanation:
Hope this will help:)
A m8 the rule is to divide by 2
Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence
. - Equally as likely to be a boy or a girl, hence
.
The probability of one of each is P(X = 1), hence:


0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377
Alright, I'm pretty sure I can help.
Let's look at the first answer choice.
7 - 2 (m + 1)
Distribute -2 and add the remaining numbers to get the total for that answer choice.
7 - 2m - 2
Simplify. You get 5 - 2m.
Looks like we found the answer on the first choice!
The Final Answer is 7 - 2 (m + 1)