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nikitadnepr [17]
3 years ago
11

What is the length of the diagonal of a rectangle with a base of 4 and an altitude of 3

Mathematics
2 answers:
icang [17]3 years ago
7 0

Answer:5



Step-by-step explanation:


alexandr1967 [171]3 years ago
5 0
5.
the diagonal squared = base squared + altitude squared.
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Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
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Step-by-step explanation:

The scale factor is 12/6 = 10/5 = 2.

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10090 7 Each railroad car in a train set is 6 inches in length. The railroad track is 5 feet long. How many railroad cars can it
Orlov [11]

Step-by-step explanation:
Given,
Length of railroad car = 6 inches
The length of railroad track = 5 feet
We will convert this length into inches.
1 feet = 12 inches
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Which is the answer for -1/3y + 4 = 3
N76 [4]

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Step-by-step explanation:

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3 years ago
Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I
inn [45]

Answer:

See explanation

Step-by-step explanation:

1. Factor the function f(x)=-2x^2+16x-30:

f(x)=-2x^2+16x-30=-2x^2+6x+10x-30=-2x(x-3)+10(x-3)=-2(x-3)(x-5).

2. The zeros (or the solutions of the equation f(x)=0) are x=3 and x=5. So? points (3,0) and (5,0) are the points on the graph that are the solutions of the equation.

3. Find the vertex:

x_v=-\dfrac{b}{2a}=-\dfrac{16}{2\cdot (-2)}=4,\\ \\y_v=-2\cdot 4^2+16\cdot 4-30=-32+64-30=2.

Thus, the coordinates of the vertex are (4,2) and the axis of symmetry is the vertical line that passes trough the vertex: x=4.

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