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navik [9.2K]
3 years ago
6

Find the area of this parallelogram. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0
182 ft squared is the answer
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Find the common ratio of the geometric sequence 9, -18, 36, ...
Anna35 [415]

Answer:

-2

Step-by-step explanation:

Each term is being multiplied by -2.

9(-2) → -18

-18(-2) → 36

6 0
3 years ago
More math help pls. :)
Step2247 [10]

By using trigonometric relations, we will see that x = 9.97°.

<h3>How to find the missing angle?</h3>

First, we need to find the bottom cathetus of the smaller triangle, we will use the relation:

Tan(θ) = (opposite cathetus)/(adjacent cathetus).

Where:

  • θ = 26°
  • Adjacent cathetus = k
  • Opposite cathetus  = 55ft.

Replacing that we get:

Tan(26°) = 50ft/k

Solving this for k, we get:

k = 55ft/tan(26°) = 112.8 ft

Now, we can see that the longer triangle adds 200ft to this cathetus, so now we will have:

  • angle = x
  • opposite cathetus = 55ft
  • adjacent cathetus = 112.8ft + 200ft = 312.8ft.

Then we have:

Tan(x) = (55ft/312.8ft)

Using the inverse tangent function in both sides, we get:

x = Atan(55ft/312.8ft) = 9.97°

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

6 0
2 years ago
2 1/3 −1.5x=12.3 please help me I'm really struggling need an answer ASAP.
Harrizon [31]

Answer:

-6.64

Step-by-step explanation:

since you need to find the value of x , but all values to one side and have x on the other .. meaning :

2 1/3 -12.3 = 1.5x

now that you have this find the decimal value of 2 1/3

which is 2*3 +1 = 7/3

in decimal form is 2.33333...

now subtract  (2.3333.. - 12.3 ) / 1.5

x = -6.6444

to 3 sf = -6.64

7 0
3 years ago
What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?
Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

3 0
4 years ago
Read 2 more answers
Es
cupoosta [38]

Answer:

-2 15 ...................

8 0
3 years ago
Read 2 more answers
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