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navik [9.2K]
3 years ago
6

Find the area of this parallelogram. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0
182 ft squared is the answer
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bija089 [108]

Answer:

Large pizza is the answer

6 0
3 years ago
What is 3/12 divided by 7
Aneli [31]
3/12 is 0.25.
0.25/7 is 0.035714
3 0
3 years ago
Read 2 more answers
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
A " Daily Number " lottery has a three-digit number from 000 to 999. You buy one ticket each day. Your number is 389. a) What is
Pachacha [2.7K]

THIS IS THE COMPLETE QUESTION BELOW;

Daily Number " lottery has a three-digit number from 000 to 999. You buy one ticket each day. Your number is 389.

a) What is the probability of winning next Tuesday and Wednesday

b)You won on Tuesday. What's the probability of winning on Wednesday?

c)You didn't win on Tuesday. What is the probability of winning on Wednesday?

Answer:

a)The probability of winning next Tuesday and Wednesday=1/1,000,000

b)if you won on Tuesday The probability of winning on Wednesday=1/1000=0.001

c)If you didn't win on Tuesday The probability of winning on Wednesday=1/1000=0.001

Step by step Explanation:

In this question we have three-digit number from 000 to 999.irrespective of the number you pick,

The probability that you will win always remains 1/1000, whether you you have been playing for ten years and you didn't win or you have won thrice .

This can be explained with the situation of when you flipp coins, If you flip a fair coin for like ten times and get tails all through in a row, the chance to get that tail on the eleventh time is still 50/50

a)The probability of winning on next Tuesday and Wednesday is calculated as;

P(of winning on next Tuesday)=1/1000

P(of winning on next Wednesday)=1/1000

Then ,P(of winning on next Tuesday and Wednesday)=(1/1000)*(1/1000),

= 1/1,000,000

b) if you won on Tuesday,

P( of winning on Wednesday)= 1/1000.

c) if you didn't win on Tuesday,

P(of winning on Wednesday) = 1/1000.

6 0
3 years ago
A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.025. To find
Ostrovityanka [42]

Answer:

Binomial probability

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

Step-by-step explanation:

For each computer, there are only two possible outcomes. Either they fail, or they do not. The probability of a computer failing is independent from the probability of other computers failing. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 125, p = 0.025

To find the probability that exactly 20 of the computers will require repair on a given day, one will use what type of probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

6 0
3 years ago
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