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Naddika [18.5K]
3 years ago
14

(-2i)(5i)(-1) how do you solve by simplifying showing the steps

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0
i = \sqrt{-1}

This is the fundamental property of i that you'll need to keep in mind when solving any problem with imaginary numbers (5i, 2i, 18i, etc.) or complex numbers (3+2i, 8-5i, etc). Squaring both sides of this definition, we also get that

i^2=-1

Which we can use to solve this problem. We have:

(-2i)(5i)(-1)\\
=(-10i^2)(-1)\\
=(-10)(-1)(-1)\\
=-10
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Solve the inequality.
Dovator [93]

The option c) x < -24 represents the solution set of the given inequality.

<u>Step-by-step explanation</u>:

The given inequality is −1/4x−12 > −6

<u>To find the solution set :</u>

Keep the x term on one side and constants on other side of the inequality.

-1/4x > -6+12

-1/4x > 6

-x > (6\times4)

-x > 24

Multiply both sides with -1 to remove the negative sign of x.

While multiplying or dividing a negative number in an equality, the inequality sign must be flipped.

⇒ x < -24

5 0
4 years ago
Which missing piece of information would allow the triangles in the figure to be proven congruent by AAS? answer: A) ∠C ≅ ∠L B)
anzhelika [568]

Answer:

B) ∠B ≅ ∠K

Step-by-step explanation:

The Angle-Angle-Side Postulate (AAS) states that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.

Given that ∠A ≅ ∠J and AC ≅ JL, then we need that ∠B ≅ ∠K to satisfy postulate AAS (the two angles are ∠A and ∠B in one triangle and ∠K and ∠J in the other one, and the non-included side is AC in one triangle and JL in the other one).

7 0
3 years ago
For f(x)= 7x+13, find f(x) when x= -3.
wariber [46]
 f(x) = 7x + 13
f(-3) = 7(-3) + 13
f(-3) = -21 + 13
f(-3) = -8
8 0
3 years ago
Plz help I need this today
n200080 [17]

63.8, hope this helps


4 0
3 years ago
Explain please
TiliK225 [7]

Answer:

n=150

Step-by-step explanation:

(-17+n/5)-13=0

-17= -17/1 = -17(5)/5

-17(5)+n/5 = n-85/5

(n-85)/5-13=0

13=13/1 =13(5)/5

(n-85)-(13(5))/5 =n-150/5

(n-150)/5=0

n-150=0

n=150

7 0
3 years ago
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