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xeze [42]
3 years ago
14

Identify the solution set of 3 In 4 = 2 In x. -{6} -{-8,8} -(8)

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Option C: The solution set is \{8\}

Explanation:

The expression is 3 \ln 4=2 \ln x

Now, let us find the solution set.

Switch sides, we get,

2 \ln x=3 \ln 4

Dividing by 2 on both sides, we have,

\ln x=\frac{3 \ln 4}{2}

Thus,  \ln 4=\ln 2^2=2\ln 2

Hence, the above expression becomes,

\ln x=\frac{3 \cdot 2 \ln (2)}{2}

Simplifying, we get,

\ln x=3 \ln 2

Applying the log rule, we get,

$$\ln x$=\ln \left(2^{3}\right)$

Simplifying, we have,

$$\ln x$=\ln \left8\right$

Applying the log rule, we have,

x=8

Thus, the solution set is \{8\}

Hence, Option C is the correct answer.

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4/6 + 1/12. Quick answer.
Fynjy0 [20]

nvm lol 3/4( had to redo

6 0
3 years ago
Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo
aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find  (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5

and (g+h)(x) is given by

g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5

and (g-h)(3) is given by

-10(3)+5\\\\=-30+5\\\\=-25

Hence, our required values would be -10x+5, 2x+5 and -25.

5 0
3 years ago
A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
Gabriella was offered a job after college earning a salary of $50,000. She will get a
inn [45]

Answer:the 3 firts and the last one

Step-by-step explanation:

I just did it

7 0
2 years ago
If the discriminant of a quadratic equation is positive, which of the following is true of the equation?
Yanka [14]
For this case suppose that we have a quadratic equation of the form:
 ax ^ 2 + bx + c

 The solution to the quadratic recuacion is given by:
 x =  \frac{-b +/-  \sqrt{b^2 - 4ac}}{2a}
 Where,
 The discriminant is:
 b ^ 2 - 4ac

 When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
 Answer:
 
B. it has two real solutions
3 0
3 years ago
Read 2 more answers
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