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mixer [17]
3 years ago
10

Which statement about rational numbers is true?

Mathematics
1 answer:
Ilya [14]3 years ago
6 0

Answer:

im not to good at math but im pretty sure that its 1. all rational numbers ae fractions

Step-by-step explanation:

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Each number in the following sequence has the same relationship to the number immediately before it. How can you find the next n
olga nikolaevna [1]

Answer:

30,000

Step-by-step explanation:

So let’s look at the numbers, It’s 3,30,300, 3000. It looks like they are 10x each next number. So the next one should be 30,000

7 0
3 years ago
Read 2 more answers
A container is shaped like a cylinder with half spheres on each end. The cylinder has a length of 30 centimeters and a radius is
Crank

The cubic centimeter one container can hold is 2,878.33 cm³.

<h3>What is the  cubic centimeter one container can hold ?</h3>

In order to determine the  cubic centimeter one container can hold, the volume of the container has to be determined.

Volume of the container = volume of the cylinder + (2 x volume of the hemisphere)

Volume of the cylinder = πr²h

Where:

  • π = 3.14
  • r = radius
  • h = height

3.14 x 5² x 30 = 2355 cm³

Volume of a hemisphere = (2/3) x π x r³

2 x (2/3 x 3.14 x 5³) = 523.33 cm³

Volume of the container =  523.33 cm³ + 2355 cm³ = 2,878.33 cm³

To learn more about the volume of a hemisphere, please check: brainly.com/question/26840364

#SPJ1

7 0
2 years ago
You play the following game against your friend. You have 2 urns and 4 balls One of the balls is black and the other 3 are white
Rom4ik [11]

Answer:

Part a: <em>The case in such a way that the chances are minimized so the case is where all the four balls are in 1 of the urns the probability of her winning is least as 0.125.</em>

Part b: <em>The case in such a way that the chances are maximized so the case  where the black ball is in one of the urns and the remaining 3 white balls in the second urn than, the probability of her winning is maximum as 0.5.</em>

Part c: <em>The minimum and maximum probabilities of winning  for n number of balls are  such that </em>

  • <em>when all the n balls are placed in one of the urns the probability of the winning will be least as 1/2n</em>
  • <em>when the black ball is placed in one of the urns and the n-1 white balls are placed in the second urn the probability is maximum, as 0.5</em>

Step-by-step explanation:

Let us suppose there are two urns A and A'. The event of selecting a urn is given as A thus the probability of this is given as

P(A)=P(A')=0.5

Now the probability of finding the black ball is given as

P(B)=P(B∩A)+P(P(B∩A')

P(B)=(P(B|A)P(A))+(P(B|A')P(A'))

Now there can be four cases as follows

Case 1: When all the four balls are in urn A and no ball is in urn A'

so

P(B|A)=0.25 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.25*0.5)+(0*0.5)

P(B)=0.125;

Case 2: When the black ball is in urn A and 3 white balls are in urn A'

so

P(B|A)=1.0 and P(B|A')=0 So the probability of black ball is given as

P(B)=(1*0.5)+(0*0.5)

P(B)=0.5;

Case 3: When there is 1 black ball  and 1 white ball in urn A and 2 white balls are in urn A'

so

P(B|A)=0.5 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.5*0.5)+(0*0.5)

P(B)=0.25;

Case 4: When there is 1 black ball  and 2 white balls in urn A and 1 white ball are in urn A'

so

P(B|A)=0.33 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.33*0.5)+(0*0.5)

P(B)=0.165;

Part a:

<em>As it says the case in such a way that the chances are minimized so the case is case 1 where all the four balls are in 1 of the urns the probability of her winning is least as 0.125.</em>

Part b:

<em>As it says the case in such a way that the chances are maximized so the case is case 2 where the black ball is in one of the urns and the remaining 3 white balls in the second urn than, the probability of her winning is maximum as 0.5.</em>

Part c:

The minimum and maximum probabilities of winning  for n number of balls are  such that

  • when all the n balls are placed in one of the urns the probability of the winning will be least given as

P(B|A)=1/n and P(B|A')=0 So the probability of black ball is given as

P(B)=(1/n*1/2)+(0*0.5)

P(B)=1/2n;

  • when the black ball is placed in one of the urns and the n-1 white balls are placed in the second urn the probability is maximum, equal to calculated above and is given as

P(B|A)=1/1 and P(B|A')=0 So the probability of black ball is given as

P(B)=(1/1*1/2)+(0*0.5)

P(B)=0.5;

5 0
3 years ago
You have 8 dime you trade each dime for 10 pennies. How mainly pennies will you have?
laila [671]
Youll have 80 pennies. dime=.10    10x8=80
6 0
3 years ago
Read 2 more answers
Work out<br> 55<br> % of <br> 2900
riadik2000 [5.3K]
Change 55% to 0.55
0.55 x 2900 = 1595
4 0
3 years ago
Read 2 more answers
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