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Assoli18 [71]
2 years ago
5

6 m 5.2 m 9 m 6 m 6 m What is the volume?

Mathematics
1 answer:
koban [17]2 years ago
4 0

Answer:

10108.8 is what i got on calculator..? please dont hate on me if its wrong

Step-by-step explanation:

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Question 3
choli [55]

Answer:

((19)(49)/98)

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What would you have to do to change 10 cubic feet into cubic inches?
Alina [70]

A. Divide by 46,656

B. Multiply by 1,728

C. Divide by 1,728

D. Multiply by 46,656

THE ANSWER IS B MULTIPLY BY 1,728


5 0
2 years ago
On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if
postnew [5]
To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12

ANSWER:
5/12 of the fish she catches are trout
7 0
2 years ago
Simone paid $13 for an initial year's subscription to a magazine. The renewal rate is $8 per year. This situation can be represe
elixir [45]

Data Input

Simone paid $13 for an initial year's

The renewal rate is $8 per year

Equation

y = 8x + 13

Table

x (number of years renewed) | (total cost in dollars)

0 -> 13 dollars

1 -> 21 dollars

2 -> 29 dollars

3 -> 37 dollars

4 -> 45 dollars

7 0
1 year ago
Suppose a Hispanic Heritage festival is held in an area measuring 2,494 square yards. If the length of the festival is 58 yards,
Kaylis [27]

Answer: 43 yards.

Step-by-step explanation:

Let the shape of the area occupied for festival be rectangle.

and area of rectangle = length x width

Given: Area of the festival= 2,494 square yards.

Length of the festival=  58 yards

Then width = (Area )÷ (length)

=  (2494)÷58  yards

= 43 yards

hence, the  width of the festival = 43 yards.

4 0
2 years ago
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