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JulijaS [17]
3 years ago
13

Lucy is a waitress. At the end of the night she must give 12% of her tips to the cleaning crew. How much does she go home with i

f she made $320 in tips last night?
Mathematics
2 answers:
erik [133]3 years ago
6 0
She gives 38.4 to the cleaners. So $281.60
olasank [31]3 years ago
6 0

Answer:

It would be $281.60

Step-by-step explanation:

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what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth? will appreciate all the help
Sidana [21]
\text {Distance =}  \sqrt{((Y_2-Y_1)^2+(X_2-X_1)^2}

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8 0
3 years ago
Identify the inequality that represents the following problem "Two more than three times a number is at least eight" What is the
lesantik [10]

The right answer is Option C.

Step-by-step explanation:

Given word problem is;

Two more than three times a number is at least eight

Let,

n be the number.

Times a number = 3n

Two more means addition;

Two more than three times a number = 3n+2

At least eight means that it can either be 8 or more.

Therefore,

3n+2≥8 is the solution set.

The right answer is Option c.

Keywords: linear inequality, solution set

Learn more about linear inequalities at:

  • brainly.com/question/13101704
  • brainly.com/question/13113987

#LearnwithBrainly

5 0
3 years ago
anita has two sisters and three brothers. the mean of all their ages is 6 years. what will their mean age be 10 years from now?t
pogonyaev
Answer:
Now: 6 yr mean age
in 10 yrs? 16 yr mean age
in 20 yrs? 26 yr mean age

Why?  Because regardless of the relationship between each sibling's age, your always adding the 10yrs to each individual, which you are then dividing out to determine the mean age.  See proof below:

Including anita, there are 6 people.  We'll define each age as an unknown variable.  Assume we know nothing about the relationships between their ages

for example sake
anita's age = a
sister 1's age = b
sister 2's age = c
brother 1's age = d
brother 2's age = e
brother 3's age = f

Now:
mean age = (a + b + c + d + e + f)/(6 people) = 6 yrs

in 10 yrs:
mean age = ((a+10) + (b+10) + (c+10) + (d+10) + (e+10) + (f+10))/(6 people)
mean age = (a + b + c + d + e + f + 60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + (60)/(6 people)
mean age = (a + b + c + d + e + f)/(6 people) + 10

Notice the first term is the same expression of the mean age for "Now"
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The same principle applies for "x" yrs from now, as long as we know what the mean age is "Now"









3 0
3 years ago
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