All categories

3 years ago

Solve for c a= b+c/d

1 answer:

4 0

B+c/d=a subtract b from both sides

c/d=a-b multiply both sides by d

c=d(a-b) or if you prefer

c=ad-bd

Note: if you meant a=(b+c)/d, multiply both sides by d

b+c=ad subtract b from both sides

c=ad-b

You might be interested in

-6<br><img src="https://tex.z-dn.net/?f=%20-%206%20%2B%203%20%5Ctimes%204%20-%2011" id="TexFormula1" title=" - 6 + 3 \times 4 -

ipn [44]

The answer is -5

Explanation:

-6 + 3 x 4 -11=
-6 + 12 -11=
+ 6 -11 = -5

4 0

3 years ago

Read 2 more answers

Answer quick please! Help fast!!

kolezko [41]

C, because when you add 45 on both sides, and then after that when you have to subtract 15 in both sides, you get 0 = 120.

8 0

3 years ago

Solve the combined inequality and describe the graph of the solution.

Vikki [24]

I hope this helps you

4x>-4 x>-1

8x <32 x <4

-1 <x <4

3 0

3 years ago

Can someone solve this

77julia77 [94]

Answer:

A ≈ 269.81 cm²

Step-by-step explanation:

This shape is a hexagon (it has 6 sides) so let's use the formula for the area of a hexagon.

A = $\frac{3\sqrt{3} }{2} s^{2}$

Where s is the length of the sides

Substitute:

A = $\frac{3\sqrt{3} }{2} s^{2}$

A = $\frac{3\sqrt{3} }{2} 10^{2}$

Solve:

A = $\frac{3\sqrt{3} }{2} 10^{2}$

A = $\frac{3\sqrt{3} }{2} 100$

Multiply the numerator:

A = $\frac{3\sqrt{3} }{2} 100$

A ≈ $\frac{5.12 }{2} 100$

(The numerator reflects a rounded number, but the actual calculations are exact)

Divide the fraction:

A ≈ $\frac{5.12 }{2} 100$

A ≈ 2.6(100)

Multiply:

A ≈ 2.6(100)

A ≈ 269.81 cm²

Therefore, the area is approximately 269.82 cubic centimeters.

6 0

3 years ago

What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)

andre [41]

<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

$(4k + 159)^{\circ}$

And another arc, let's call it FGH. measures:

$(2k + 153)^{\circ}$

If those arc are equal, then this equation is true:

$(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3$

Substituting k into the first equation:

$\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}$

3 0

3 years ago

Read 2 more answers