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miss Akunina [59]
3 years ago
11

Plz say me answer (algebraic expressions and identities)​

Mathematics
2 answers:
STatiana [176]3 years ago
5 0

Answer:

300

Step-by-step explanation:

Apply PEMDAS.

\frac{176*176-124*124}{52}\\\\\frac{30976-15376}{52}\\\\\frac{15600}{52}\\\\\boxed{300}

Hope this helps.

MissTica3 years ago
4 0

Step-by-step explanation:

30976-15376/52

15600/52

300

so,300 is the final ans.

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Solve the simultaneous Equation using the two <br> methods<br>4m=n +7<br>3m+ 4n+9=0​
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Elimination method:

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3m + 4n + 9 = 0

<em>First, let's get the equations in the same form.</em>

4m - n - 7 = 0

3m + 4n + 9 = 0

<em>Now let's make multiply the first equation by 4 so we can eliminate n.</em>

16m - 4n - 28 = 0

+3m + 4n + 9 = 0

<em>Now we can add the equations.</em>

16m + 3m - 4n + 4n - 28 + 9 = 0

19m + 0n - 19 = 0

19m - 19 = 0

19m = 19

<em>m = 1</em>

<em>Now we put m back into one (or both) of the original equations.</em>

4(1) = n + 7

4 = n + 7

<em>n = -3</em>

<em>If you plug m into the other equation, you get the same result.</em>

<em />

Substitution method:

4m = n + 7

3m + 4n + 9 = 0

<em>With this method, we plug one of the equations into the other one. I'm going to use m in the second equation as a substitute for m in the second equation.</em>

3m + 4n + 9 = 0

3m = -4n - 9

m = (-4/3)n - 3

<em>Now I can substitute the right side into the first equation like so:</em>

4[(-4/3)n - 3] = n + 7

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(-16n)/3 = n + 19

-16n = 3(n + 19)

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0 = 16n + 3n + 57

0 = 19n + 57

0 = 19n/19 + 57/19

0 = n + 3

<em>-3 = n</em>

<em>And then we put that back into one of the original equations.</em>

4m = n + 7

4m = -3 + 7

4m = 4

<em>m = 1</em>

Hopefully you learned something from this.

5 0
3 years ago
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