Answer:
10 lb of cashews and 70 lb of peanuts
Step-by-step explanation:
Let x = the pounds of cashews.
Then 80 – x = the pounds of peanuts
Value of cashews + value of peanuts = volume of mixture
x×4.75 + (80 – x)×2.75 = 80×3 Remove parentheses
4.75x + 220 - 2.75x = 240 Combine like terms
2.00x + 220 = 240 Subtract 220 from each side
2.00x = 20 Divide each side by 2.00
x = 10 lb
80 - x = 80 – 10
80 - x = 70 lb
Max will mix 10 lb of cashews with 70 lb of peanuts.
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<em>Check:
</em>
10×4.75 + 70×2.75 = 80×3.00
47.50 + 192.50 = 240.00
240.00 = 240.00
Using P(A∪B) = P(A) + P (B) - P(A∩B)
If we apply this in the question
Then P(S∪T) = P(S) + P(T) - P (S∩T)
= 6/11 + 1/10 - P (S∩T)
= 71/110 - P (S∩T)
But events S and T are mutually exclusive events therefore,
P(S∩T) = 0,
Hence P(S∪T) = 71/110
Answer:
9/4
Step-by-step explanation:
1. 
2. 
3. 
Therefore, the slope is 9/4.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
