All categories

3 years ago

I'll give brainliest

Mathematics

2 answers:

avanturin [10]3 years ago

7 0

Hey There!

In order to solve this you need to factor f(x) = x^3 - 19x + 30 Entirely.

When you do that you get these factors;

f(x) = (x – 2) (x – 3) (x + 5)

From there you play 'elimination'

A) There is no listed factor for (x + 2)

B) There is no listed factor for (x + 3)

C) There is a listed factor for (x + 5)!

D) There is no listed factor for (x - 5)

Hope I helped, Five Stars & Brainliest always helps!

erma4kov [3.2K]3 years ago

6 0

Answer:

I think its D sorry if I get it wrong

Step-by-step explanation:

You might be interested in

What's 0.00045 in scientific notation

tino4ka555 [31]

0.00045 = 4.5 × 10^-4

8 0

3 years ago

Read 2 more answers

If r(x)=2-x^2 and w(x)=x-2, what is the range of (w*r)(x)

horrorfan [7]

First, find the product (w*r)(x): (w*r)(x) = (x-2)*[2-x^2] = 2x - x^3 - 4 + 2x^2

This is a cubing function. Since the sign of the cube-of-x term is negative, the graph will begin in Quadrant II and pass through Quadrant IV. There are no limits on y. Thus, the range is (-infinity, +infinity).

5 0

3 years ago

Read 2 more answers

Solve the following system of equations. 3x + 2y - 5 = 0 x = y + 10

Dominik [7]

Y=-5
x=5
there's the answer

6 0

3 years ago

Read 2 more answers

Raj and aditi like to play chess against each other. aditi has won 12 of the 20 games so far. they decide to play more games. ho

Novay_Z [31]

Answer:

How many more games will Aditi have to win to have an 80% winning record?

The linear equation that models this is:

12 + x = 0.80(x+20)

Aditi would have to win 20 more games to have an 80% winning record.

Rate as brainliest and plz press the THANKS button :)

4 0

3 years ago

Read 2 more answers

2 A boat costs $18,800 and decreases in value by 12% per year. How much will the boat be worth after 13 years?

11111nata11111 [884]

$\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &18800\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ t=\textit{elapsed time}\dotfill &13\\ \end{cases} \\\\\\ A=18800(1-0.12)^{13}\implies A=18800(0.88)^{13}\implies A\approx 3568.0636019$

6 0

3 years ago