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stiks02 [169]
3 years ago
5

Classify the expression, name the operation(s) and identify any variables. 3s – 5

Mathematics
1 answer:
Elodia [21]3 years ago
8 0
Numerical, subtraction, s
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What is one of the zeros of the
Sphinxa [80]

Answer:

x=-3 and x=1 are 2 zeros shown on the graph

Step-by-step explanation:

7 0
3 years ago
8. The diagram of a living room is shown below. What fractions of the living room is covered by the rug?​
Airida [17]

Answer:

there is no diagram

Step-by-step explanation:

8 0
3 years ago
X2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is
erastova [34]

The Standard form of the equation of circle is (x+21)² + (y+19)² = 849

<h3>What is Standard form of circle?</h3>

To transform general form to a standard form, you can use completing the square method or you can convert this equation

x² + y² + Dx + Ey + F = 0 to x² + y² + (-2h)x + (-2k)y + (h²+k²-r²) = 0

Here, Given: x² + y² + 42x + 38y − 47 = 0

Required: Find the values of h, k, and r using this formula

x² + y² + (-2h)x + (-2k)y + (h²+k²-r²) = 0

On comparing we get,

-2h = 42

  h = 21

-2k = 38

 k = 19

-47 = h² + k² - r²

-47 = 21² + 19² - r²

   r² = 849

  r = √849

Thus, the Standard form of the equation of circle is (x+21)² + (y+19)² = 849

Learn more about Circle from:

brainly.com/question/11833983

#SPJ1

7 0
2 years ago
If ab = 49 and bc = 22, find the length of ac
Misha Larkins [42]

Answer:

ac = 71

Step-by-step explanation:

ac = ab + bc

ac = 49 + 22

ac = 71

3 0
3 years ago
Use the perimeter to find the length of segment AD. This is the distance from A to D. Explain how you found your answer. Please
jekas [21]

Answer:

AD = 5 units

Step-by-step explanation:

Given:

Perimeter = 18 units

BC = 4 units

CD = 3 units

Required:

Length of segment AD

Solution:

Perimeter = AB + BC + CD + AD

We can easily find AB,

AB = 6 units (distance from A to B)

Plug in the values

18 = 6 + 4 + 3 + AD

18 = 13 + AD

Subtract 13 from each side

18 - 13 = 13 + AD - 13

5 = AD

AD = 5 units

5 0
3 years ago
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