First, illustrate the problem into a diagram like the one shown in the attached picture. The component vectors are shown in red (y-component) and blue (x-component). Since this is a right triangle, let's apply the trigonometric functions of sine and cos.
y-component, vy:
sin (π/3) = vy/8
vy = 6.928x-component, vx:
cos (π/3) = vx/8
vx = 4
Answer:
At midnight, the temperature was 43.7 degrees above 0, and in the morning, it was 3.6 degrees below 0
Step-by-step explanation:
At midnight, the temperature was 43.7°F. In the morning, the temperature was −3.6°F.
We can say that −3.6 lie on the LHS of a number line while 43.7 lie on RHS of the number line and 0 at the mid.
43.7°F is above 0 and 3.6°F is below 0.
At midnight, the temperature was 43.7 degrees above 0, and in the morning, it was 3.6 degrees below 0
. Hence, the correct option is (d).
An algebraic expression to represent the value of this car after M months is y=Mx+C.
We have given that the
The straight-line depreciation equation for a car is,
y = -2,680x + 26,800.
therefore after 4moths
y = -2,680(4) + 26,800.
y = -10720 + 26,800.
y=16080
<h3>
What is the slope?</h3>
The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)
b. For find after the 75 months replace x by 75 and slolve the given inequality.
Suppose that M represents the length of time in months when
the car still has value.
An algebraic expression to represent the value of this car after M months.
y=Mx+C.
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Answer:
x = 6
Step-by-step explanation:
8 - 2 = 6
7(8 - 2) = 7(6)
7x6 = 42, so
x = 6 is the correct answer
