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2 years ago

2x^2-3x=0 helppppppppppp with steps pls

Mathematics

1 answer:

trapecia [35]2 years ago

8 0

Answer:

x=0, x=3/2

Step-by-step explanation:

2x^2-3x=0

Factor out an x

x(2x-3) =0

Using the zero product property

x = 0 2x-3 =0

Add 3 to each side

2x-3+3 =0+3

2x =3

divide each side by 2

2x/2 = 3/2

x=3/2

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2 years ago

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Step-by-step explanation:

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2 years ago

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Alekssandra [29.7K]

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3 years ago

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olga55 [171]

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Step-by-step explanation:

Please, see the attached file.

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4 0

2 years ago

The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?

Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are $(x_{1}, y_1)$ and $(x_2, y_2)$ then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

$(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})$

Thus for our question the endpoints are $(x_E, y_E)$ and $(x_F, y_F)$ and hence the midpoint will be:

$(x_M, y_M)=$ $(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})$

Thus, Option C is the correct option.

6 0

3 years ago