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8_murik_8 [283]
3 years ago
9

Which equation, when solved, results in a different value of x than the other three?

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
I would have to say -7(1/8)x-4/3=20.


The first and the second one both result in
-23 5/7

The last one results in -24 8/21

but the third one is -22 3/8.

So your answer is either the third of the last one. I assumed the third because, it is lower than all others and the first two are closer to 24 than they are to 22. It’s your choice on how to judge it.
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What is d+15-9/3+5 PLZZZZZ
zloy xaker [14]
D + 15 - 9 / 3 + 5 the answer is : d + 17
3 0
3 years ago
Solve for x: 3(x + 1) = −2(x − 1) − 4
Anika [276]
Solve your equation step-by-step.

3(x+1)=−2(x−1)−4


Simplify both sides of the equation.

3(x+1)=−2(x−1)−4

Simplify:

3x+3=−2x−2

Add 2x to both sides.

3x+3+2x=−2x−2+2x

5x+3=−2

Subtract 3 from both sides.

5x+3−3=−2−3

5x=−5

Divide both sides by 5.

5x/5 = −5/5

x=−1


4 0
3 years ago
Find the slope of the curve r=cos(2theta) at theta=pi/6.. . Must this be solved parametrically? If so, why?
lara31 [8.8K]

By converting into parametric equations,

<span><span>x(θ)=r(θ)cosθ=cos2θ<span>cosθ
</span></span><span>y(θ)=r(θ)sinθ=cos2θsinθ</span></span>

By Product Rule,

<span>x'(θ)=−sin2θcosθ−cos2θsinθ</span>

<span>x'<span>(π/2)</span>=−<span>sin(π)</span><span>cos<span>(π/2)</span></span>−<span>cos(π)</span><span>sin<span>(π/2)</span></span>=1</span>

<span>y'(θ)=−sin2θsinθ+cos2θcosθ</span>

<span>y'<span>(π/2)</span>=−<span>sin(π)</span><span>sin<span>(π/2)</span></span>+<span>cos(π)</span><span>cos<span>(π/2)</span></span>=0</span>

So, the slope m of the curve can be found by

<span>m=<span>dy/dx</span><span>∣<span>θ=<span>π2
</span></span></span>= <span><span>y'<span>(π/2)/</span></span><span>x'<span>(π/2)
</span></span></span></span>=0/1

=0

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

6 0
3 years ago
Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T
Dahasolnce [82]

Answer:

(a) [8, 14]

(b)  8 \leq x \leq 14

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

|11-x|\leq3

Solving the absolute inequality

-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.

5 0
3 years ago
Read 2 more answers
Make up a problem using the chart below 100 200 300 books toys notebook ?
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3 0
3 years ago
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