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tester [92]
3 years ago
11

How many times can 15 go into 19

Mathematics
2 answers:
Pavel [41]3 years ago
7 0

Answer:

1 4/19

Step-by-step explanation:

15 into 19 is 1 r4 and as a mixed number its 1 4/19.......

I might be wrong but that's what i  got!

maks197457 [2]3 years ago
3 0

Answer:

1 time, unless in decimal form which is 1.266666666(infinite)66666667

Step-by-step explanation:

15x1=15

15x2=30

30 is too high, so 15 is the only option.

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How do you differentiate y = 3x3 - 2x-4
riadik2000 [5.3K]

Answer:

y' = 9x^2 + 8x^-5

Step-by-step explanation:

General Principle

y' = ax^b

y' = a*b * x^(b-1)

Solution

3x^3 = 3*3x^(3-1)

3x^3 = 9x^2

-2x^-4  = -2*-4 x ^(-4 - 1)

-2x^-4 = 8 x ^-5

Answer

y' = 9x^2 + 8x^-5

7 0
3 years ago
Whats is the estimate of 145.5÷21
____ [38]

Answer:

the estimate of 145.5÷21 is 6.9 or 6. 93

Step-by-step explanation:

6 0
3 years ago
Can you Solve. 3x^2+10x+3
Alika [10]
You cannot solve for x but you can factor

to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y

so solve

3 times 3=9

what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so

3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)

(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)

6 0
3 years ago
Read 2 more answers
Mr. Foster paid $160 to rent a car for 5 days. If the cost for each day was the same, how much did he pay each day that he rente
Eddi Din [679]

Answer is 32

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
RS=2x-8, ST = 11, RT = x+10
ziro4ka [17]

Answer:

Equation~=~\Large\boxed{2x+3=x+10}

x~=~\Large\boxed{7}

RS~=~\Large\boxed{6}

RT~=~\Large\boxed{17}

Step-by-step explanation:

<u>Given information</u>

RS=2x-8

ST=11

RT=x+10

<u>Derived expression from the given information</u>

<em>Presumably, I think this is a combination of segments</em>

RS+ST=RT

<u>Substitute values into the given expression</u>

(2x-8)+(11)=(x+10)

<u>Combine like terms</u>

<em>The following is the expression</em>

\Large\boxed{2x+3=x+10}

<u>Subtract 3 on both sides</u>

2x+3-3=x+10-3

2x=x+7

<u>Subtract x on both sides</u>

2x-x=x+7-x

\Large\boxed{x=7}

<u>Substitute the x value into corresponding expressions to determine the final value</u>

RS=2x-8=2(7)-8=14-8=\Large\boxed{6}

RT=x+10=(7)+10=\Large\boxed{17}

Hope this helps!! :)

Please let me know if you have any questions

3 0
1 year ago
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