we can convert any decimal value to a fraction by simply <u>using in the denominator a power of 10 with as many zeros as there are decimals and lost the dot above</u>, this one has one decimal, so we'll use 1 zero, and lose the dot above.
![\bf 0.\underline{6}\implies \cfrac{06}{1\underline{0}}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 3}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 50}\implies \cfrac{3}{50}](https://tex.z-dn.net/?f=%5Cbf%200.%5Cunderline%7B6%7D%5Cimplies%20%5Ccfrac%7B06%7D%7B1%5Cunderline%7B0%7D%7D%5Cimplies%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%203%7D%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%2050%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B50%7D)
Multiply <u>√2</u> by <u>√72</u>. The product is a <u>rational</u> number because <u>√144</u> can be simplified to an integer.
Step-by-step explanation:
As Landon has to prove that two product of two rational numbers, he has to choose two rational numbers from the list and then multiply and show that the product is also a rational number.
Let us define the rational numbers first
A number that can be written in the form of p/q where p,q are integers and q is not equal to zero, is called a rational number.
From the give =n list of rational numbers
Taking
√2 and √72

As we can see that the product of √2 and √72 is 12 which is also a rational number.
So,
Multiply <u>√2</u> by <u>√72</u>. The product is a <u>rational</u> number because <u>√144</u> can be simplified to an integer.
Keywords: Rational numbers, Product
Learn more about rational numbers at:
#LearnwithBrainly
Answer:
A=bh..I don't get for those numbers
Answer:
Usually there are the variables x y z but it doesn't matter what they are.
Step-by-step explanation:
First choose your first variable to solve. Find x by putting all the numbers and variables to one side.
once you found x substitute the answer for x in all the equations. Next find y and substitute your answer in all the equations again.
Once you have solved 2 variables then you are able to solve z.
If you have questions please feel free to ask in the comments below.