The answers are: D and C and A and E
because:
B 3(x - 5) - 2(6x2 + 9x + 5)=<span><span><span>−<span>12<span>x^2</span></span></span>−<span>15x</span></span>−<span>25
</span></span>F (4x2 - 13x - 7) - (16x2 + 9x - 5)=<span><span>−<span>12<span>x2</span></span></span>−<span>22x</span></span>−<span>2
E </span>(-15x2 + 9x - 10) + (3x2 - 10x - 5)=<span><span>−<span>12<span>x^2</span></span></span>−x</span>−<span>15</span>
Answer:
y=45x+25
Step-by-step explanation:
y=45x+25
25 is a one-time fee so it is at the end. 45 is the monthly fee so it goes in front of x.
Let us draw a picture to make the things more clear.
Attached is the image.
We have been given that
![\angle acd = 60 ^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20acd%20%3D%2060%20%5E%7B%5Ccirc%7D)
Therefore, we have
![\angle dcb =90- 60= 30 ^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20dcb%20%3D90-%2060%3D%2030%20%5E%7B%5Ccirc%7D)
Now, in triangle bcd, we have
![\tan30 = \frac{5}{cd}\\ \\ \frac{1}{\sqrt 3}=\frac{5}{cd}\\ \\ cd=5\sqrt 3](https://tex.z-dn.net/?f=%5Ctan30%20%3D%20%5Cfrac%7B5%7D%7Bcd%7D%5C%5C%0A%5C%5C%0A%5Cfrac%7B1%7D%7B%5Csqrt%203%7D%3D%5Cfrac%7B5%7D%7Bcd%7D%5C%5C%0A%5C%5C%0Acd%3D5%5Csqrt%203)
Now, in triangle acb, we have
![tan 60 = \frac{ad}{5\sqrt3} \\ \\ \sqrt 3= \frac{ad}{5\sqrt3}\\ \\ ad= 5\sqrt3 \times \sqrt 3\\ \\ ad= 5\times 3\\ \\ ad=15](https://tex.z-dn.net/?f=tan%2060%20%3D%20%5Cfrac%7Bad%7D%7B5%5Csqrt3%7D%20%5C%5C%0A%5C%5C%0A%5Csqrt%203%3D%20%20%5Cfrac%7Bad%7D%7B5%5Csqrt3%7D%5C%5C%0A%5C%5C%0Aad%3D%205%5Csqrt3%20%5Ctimes%20%5Csqrt%203%5C%5C%0A%5C%5C%0Aad%3D%205%5Ctimes%203%5C%5C%0A%5C%5C%0Aad%3D15)
Thus, ad is 15 cm.