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Katarina [22]
2 years ago
14

ONLY NUMBER 7. HELP PLEASEEEE. I START SCHOOL TOMORROW

Mathematics
2 answers:
lora16 [44]2 years ago
5 0

Answer:

(x^2) + 1 = y

Step-by-step explanation:

To check, you can just plug in the x values given. It should equal to its given y value.

natali 33 [55]2 years ago
3 0

Answer:

y = x² + 1

Step-by-step explanation:

Consider the differences in the y values

y : 1  2  5   10  17

      1   3   5   7 ← first differences are not constant so not linear

Consider the differences of the first differences

1   3   5   7

  2  2   2← second differences are constant

Because the second differences are constant the relationship is quadratic

The form of the relationship is

y = x² ± c ← where c is a constant

Substitute values of x into the relationship to find what is needed

x = 0 : y = 0² = 0 ← require to add 1 to obtain 1

x = 1 : y = 1² = 1 ← require to add 1 to obtain 2

x = 2 : y = 2² = 4 ← require to add 1 to obtain 5

x = 3 : y = 3² = 9 ← require to add 1 to obtain 10

x = 4 : y = 4² = 16 ← require to add 1 to obtain 17

Hence relationship is y = x² + 1

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HELP PLEASE! Write a quadratic function that passes through the point (-1,9), has an axis of symmetry of x=-3 and a minimum valu
xxTIMURxx [149]

Answer:

y = \frac{1}{2}x^{2} - 3x + 11.5

Step-by-step explanation:

Vertex form of a quadratic equation;

y = a( x - h )^{2} + k

Vertex of the parabolas (h, k)

The vertex of the parabola is either the minimum or maximum of the parabola. The axis of symmetry goes through the x-coordinate of the vertex, hence h = -3. The minimum of the parabola is the y-coordinate of the vertex, so k= 7. Now substitute it into the formula;

y = a ( x + 3 ) ^{2} + 7

Now substitute in the given point; ( -1, 9) and solve for a;

9 = a( (-1 ) + 3)^2 + 7\\9 = a (2)^{2} + 7\\9 = 4a + 7\\-7           -7\\2 = 4a\\\frac{1}{2} = a\\

Hence the equation in vertex form is;

y = \frac{1}{2}(x - 3)^{2} + 7

In standard form it is;

y = \frac{1}{2}x^{2} - 3x + 11.5

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2 years ago
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Step-by-step explanation:

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