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Ugo [173]
3 years ago
15

Find the distance (2,-2) and (-8,-2)

Mathematics
2 answers:
Naddik [55]3 years ago
8 0
The distance between the two is 10
erma4kov [3.2K]3 years ago
8 0

Answer:

the distnace between (2,-2) and (-8,-2) is 5.099

Step-by-step explanation:

You might be interested in
Find the magnitude of AB with initial point A(3,-1) and terminal point B(-2, 6).
Alenkasestr [34]

Answer:

Step-by-step explanation:

AB=√(-2-3)²+(6+1)²=√(25+49)=√(74)

3 0
3 years ago
Who can answer this for me please
melamori03 [73]

Answer:

<em>f(2)=-2</em>

Step-by-step explanation:

<u>Values of a function from a graph</u>

The graph of a function is usually a drawn line that joins a number of points that correspond to the ordered pairs (x,y), where x is a given value, and y is the value calculated through the rule of the function, usually a formula or equation.

If we want to know the value for a specific value of x, we find the corresponding x-coordinate, draw an imaginary vertical line until we meet the graph. The value of y at that point is the required value of the function.

For example, for x=0 the graph crosses the y-axis at y=2, thus the ordered pair is (0,2), and f(0)=2.

For x=2, the function has a value of y=-2, thus:

f(2)=-2

8 0
2 years ago
4.Find the measure of arc DF in the figure.
Vladimir79 [104]

Answer:

129 degrees

Step-by-step explanation:

Ok, DAE, as given, is 90 degrees. So, BAD would equal 90 as well, so BAC would be 90-51, 39. And because FAE is vertical angle to BAC, FAE is also 39. So 39 + 90 is 129.

7 0
2 years ago
Given: KLMN is a parallelogram, LF is perpendicular to KN, LD is perpendicular to NM, angle FLD = 35. Find angles of KLMN
Kisachek [45]

The question is four parts, It is required the angles of parallelogram KLMN

So, It is required ⇒ ∠K  , ∠L  , ∠M  and ∠N

See the attached figure which represents the explanation of the problem

========================

Part (1): Find  ∠N:

==============

in the shape FLDN

∵ LF ⊥ KN  ⇒⇒⇒ ∴ ∠LFN = 90°

∵ LD ⊥ NM ⇒⇒⇒ ∴ ∠LDN = 90°

∵ The sum of all angels of FLDN = 360°

∵ ∠FLD = 35°

∴ ∠FLD + ∠LDN + ∠DNF + ∠LFN = 360°

∴ 35° + 90° + ∠DNF + 90° = 360°

∴ ∠DNF = 360° - ( 90° + 90° + 35°) = 360° - 215° = 145°

∴ The measure of angle N = 145°

=============================

Part (2): Find  ∠M:

==============

∵ KLMN is parallelogram , ∠N = 145°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠M + ∠N = 180°

∴ ∠M = 180° - ∠N = 180° - 145° = 35°

∴ The measure of angle M = 35°

================================

Part (3): Find  ∠L:

==============

∵ KLMN is parallelogram , ∠M = 35°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠M + ∠KLM = 180°

∴ ∠KLM = 180° - ∠M = 180° - 35° = 145°

OR ∠KLM = ∠N = 145° ⇒⇒⇒  property of the parallelogram

∴ The measure of angle KLM = 145°

===================================

Part (4): Find  ∠K:

==============∵ KLMN is parallelogram , ∠N = 35°

∴ The angles N and M are supplementary angles ⇒ property of the parallelogram

∴ ∠K + ∠N = 180°

∴ ∠K = 180° - ∠N = 180° - 145° = 35°

OR ∠K = ∠M = 35° ⇒⇒⇒  property of the parallelogram

∴ The measure of angle K = 35°

7 0
2 years ago
Help me please! I would appreciate it! :)
zheka24 [161]

Answer:

-4

Step-by-step explanation:

distributing gets you to : 8h + 38 = -18 - 6h

then add 6h to 8h and you have 14h + 38 = -18

solve normally & thats how you get your answer

8 0
2 years ago
Read 2 more answers
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