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Bond [772]
3 years ago
9

Show all work to receive credit.

Mathematics
1 answer:
Helga [31]3 years ago
8 0

Answer:

angle 1= 70 degrees

angle 2= 65 degrees

angle 3= 65 degrees

angle 4 = 115 degrees

angle 5= 45 degrees

angle 6= 45 degrees

angle 7= 45 degrees

Step-by-step explanation:

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You have some money in your wallet. You don't know the exact amount, but you think you have 60 dollars give or take 15 dollars.
Karolina [17]

Answer:

The least amount is 75 dollars.

The biggest amount is 125 dollars

Step-by-step explanation:

The absolute value function will help us determine a  range of possible values since we do not know the exact amount of money.

Defining the function.

Let x be the exact amount of money in my pocket, we can define the equation

And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation.  So we can write:

We have a difference inside an absolute value, since we know the difference must be either +25 or -25.

Solving for x

Using the definition of absolute value we have

So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is

Solving for x give us

If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition

Solving for x give us

So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.

6 0
2 years ago
Ashley was 98 pounds one year ago. If she now weighs 112 pounds, what is the percent increase in her weight?
Sever21 [200]
B.14.2 because you subtract the 98 to the 112
5 0
3 years ago
Read 2 more answers
WILL GIVE LOTS OF POINTS, PLEASE HELP !!!!
Dima020 [189]

Answer:

Terminal side in 2nd Quadrant

Only sin(x) & cosec(x) are positive in 2nd Quadrant

\sin( x )  =  \frac{5}{13}  \\

Perpendicular=5

Base=√(13²-5²)=√(169-25)=√144=√12²=12

Hypotenuse=13

\cos(x)= -  \frac{12}{13}  \\ \tan(x)  =  -  \frac{5}{12}  \\  \cosec(x)  =  \frac{13}{5}  \\  \sec(x)= - \frac{13}{12}  \\\cot(x) =  -  \frac{12}{5}

7 0
2 years ago
Can someone help me with this problem asap
xenn [34]

Answer:

f(x) = $ x^4 - 2x^3 + 49x^2 - 18x + 360 $ is the required polynomial.

Step-by-step explanation:

Given the zeroes (roots) of the polynomial are $ -3i $ and $ 2 + 6i $.

We know that complex roots occur in conjugate pairs.

So, this means that $ +3i $ and $ 2 - 6i $ would also be the roots of the polynomial.

If $ \pm 3i $ are to be the roots of the polynomial then the polynomial should have been: $ x^2 + 9 = 0$.

Now, to determine the polynomial for which $ 2 \pm 6i $ would be the roots.

Roots of the polynomial are nothing but the values of x (any variable) that would make the polynomial zero.

⇒ $ x = 2 + 6i \hspace{35mm} x = 2 - 6i $

⇒ $ x - 2 - 6i = 0 \hspace{25mm} x - 2 + 6i = 0 $

The required polynomial would be the product of all the above polynomials.

$ i.e., (x^2 + 9)(x - 2 + 6i)(x - 2 - 6i) = 0 $

Multiply this to get the required equation.

⇒$ (x^2 + 9)(x^2 - 2x + 40) $

$ \implies x^4 - 2x^3 + 40x^2 + 9x^2 - 18x + 360 = 0 $

∴ The required polynomial is x⁴ - 2x³ + 49x² - 18x + 360 = 0.

3 0
3 years ago
3(x+1)-8=14-2(3x-4)
VLD [36.1K]

Answer:

  • 3x+3-8=(14-2=12)36x-48

Step-by-step explanation:

3x+3-8=36x-48

collect like terms

3x-36x=-48-3-8

-33x=-59

divide both side

-33×\+-33=-59/-33

×=59/-33 or 1.69

7 0
3 years ago
Read 2 more answers
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