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Karolina [17]
3 years ago
10

Convert 23/7 into decimal amd explain the process

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

Step-by-step explanation:

Step 1: Multiply the whole number by the denominator: 23 × 7 = 161.

Step 2: Add the product you got in Step 1 to the numerator: 161 + 7 = 168.

Step 3: Divide the sum from Step 2 by the denominator: 168 ÷ 7 = 24. That's it folks!

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Solve using substitution.<br> y = -2<br> -7x - y = -5
Natasha_Volkova [10]

Step-by-step explanation:

- 7x - ( - 2) =  - 5 \\  - 7x + 2 =  - 5 \\  - 7x =  - 7 \\ x = 1 \\

5 0
2 years ago
PLSS ANSWER
labwork [276]

\frac{3}{6}  = three \: sixths

\frac{3}{6}  +  \frac{3}{6}  =  \frac{3 + 3}{6}  =  \frac{6}{6}  = 1

<h2>Letter C</h2>
8 0
2 years ago
Prove that under root 2 is a irrational number​
torisob [31]

Answer:

Let's suppose √2 is a rational number. Then we can write it √2  = a/b where a, b are whole numbers, b not zero.

We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction. Notice that in order for a/b to be in simplest terms, both of a and b cannot be even. One or both must be odd. Otherwise, we could simplify a/b further.

From the equality √2  = a/b it follows that 2 = a2/b2,  or  a2 = 2 · b2.  So the square of a is an even number since it is two times something.

From this we know that a itself is also an even number. Why? Because it can't be odd; if a itself was odd, then a · a would be odd too. Odd number times odd number is always odd. Check it if you don't believe me!

Okay, if a itself is an even number, then a is 2 times some other whole number. In symbols, a = 2k where k is this other number. We don't need to know what k is; it won't matter. Soon comes the contradiction.

If we substitute a = 2k into the original equation 2 = a2/b2, this is what we get:

2=(2k)2/b22=4k2/b22*b2=4k2b2=2k2

This means that b2 is even, from which follows again that b itself is even. And that is a contradiction!!!

WHY is that a contradiction? Because we started the whole process assuming that a/b was simplified to lowest terms, and now it turns out that a and b both would be even. We ended at a contradiction; thus our original assumption (that √2 is rational) is not correct. Therefore √2 cannot be rational.

(I copied this from the internet, but hope it helps!)

4 0
3 years ago
Read 2 more answers
Find the first 3 iterations of the function here: g(n) = 3x if you have<br> an initial value of 2.
Tom [10]
1st it: g(2)=3(2)=6 || 2nd it: g^2(2)=3(6)=18 || 3rd it: g^3(2)=3(18)=54
4 0
3 years ago
Show work please thanks
Tju [1.3M]
Be more specific on the first one
3 0
2 years ago
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