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sdas [7]
3 years ago
7

6. There are six professors teaching the introductory dis- crete mathematics class at a university. The same final exam is given

by all six professors. If the lowest possi- ble score on the final is 0 and the highest possible score is 100, how many students must there be to guarantee
Mathematics
1 answer:
podryga [215]3 years ago
3 0

Complete question is;

There are six professors teaching the introductory discrete mathematics class at a university. The same final exam is given by all six professors. If the lowest possible score on the final is 0 and the highest possible score is 100.

How many students must there be to guarantee that there are two students with the same professor who earned the same final examination score?

Answer:

607 students

Step-by-step explanation:

To solve this question means we have to use Pigenhole principle which states that if y number of items are put into z number of containers, with y > z, then it means that that at least one container must definitely contain more than one item.

Now, let's find the number of boxes and objects:

If possible scores are from 0 to 100 with both inclusive it means number of possible scores = 101.

Now, If there was only one professor grading the students, in order to ensure that that there are two students with the same professor who earned the same final examination score,

The number of students would have to be = 101 + 1 = 102 students

Meanwhile, for each student, since there are 6 professors, the possible combination for a score will be = 6 possible combinations.

Therefore, number of students that will guarantee that there are two students with the same professor who earned the same final examination score must be a minimum of: (6 × 101) + 1 = 607

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Solve by Substitution -8x-10y=12 -7x-10y=3​
Harlamova29_29 [7]

Answer:

Point Form:

(−9,6)

Equation Form:

x=−9,y=6

Step-by-step explanation:

3 0
3 years ago
Y=4x y=-2x-6 how to sovle this
Talja [164]

Answer:


Step-by-step explanation:


Substitute 4x for Y: 4x = -2x -6


Now add 2x to both sides

(due to reciprocal, the opposite of -2x is positive 2x): 4x + 2x = -2x +2x -6


Add common like terms

(4x + 2x = 6x and -2x + 2x cancel out leaving -6 alone): 6x = 6


Now get X alone by dividing the 6 to both sides: 6x/6 = -6/6


Since you're dividing a negative and a positive, the outcome will be a negative so the answer is: X= -6


Hope this helps :)

3 0
4 years ago
How can you use properties to solve equations with a variable on both side so of the equal sign?
zubka84 [21]
Solving equations with a variable on both sides requires multiple steps. Let's look at how to solve one using properties step by step.



Example 1: 100 - 4x = 16x



Step 1: In the above equation, the first step is to identify the variable. Clearly, it is x but the variable exists on both sides of the equal sign.



Step 2: To simplify it, we can use the properties of equality (addition and multiplication property of equality) which says that if we perform an operation on one side, the same should be done on the other side of the equal sign so that the equation is balanced.



Using the addition property of equality, let's add 4x to both sides, we get.



100 - 4x + 4x = 16x +4 x



which equals, 100 = 20x



Now, dividing both sides by 20, we get



x = 5



For more complex equations, the usage of distributive property of multiplication might be needed to isolate the variable and simplify.
4 0
3 years ago
Which expression is equivalent to 3/5?
Brilliant_brown [7]
Option C!! 3/5 means 3 divided 5
7 0
3 years ago
Solid A is similar to Solid B. If the volume of Solid A is 3,240 meters cubed
irina [24]

Option B: 36 : 1 is the ratio of the surface area of Solid A to Solid B

Explanation:

Given that the Solid A is similar to Solid B.

The volume of Solid A is 3240 m³

The volume of Solid B is 15 m³

We need to find the ratio of the surface area of Solid A to Solid B.

Thus, we have,

\frac{SA \ of \ Solid A}{SA \ of \ Solid B}=\sqrt[3]{\frac{3240}{15}}

Dividing the terms, we get,

\frac{SA \ of \ Solid A}{SA \ of \ Solid B}=\sqrt[3]{\frac{216}{1}}

Taking cube root, we get,

\frac{SA \ of \ Solid A}{SA \ of \ Solid B}=\frac{6}{1}

Squaring the ratios, we get,

\frac{SA \ of \ Solid A}{SA \ of \ Solid B}=(\frac{6}{1})^2

\frac{SA \ of \ Solid A}{SA \ of \ Solid B}=\frac{36}{1}

Thus, the ratio of the surface area of Solid A to Solid B is 36 : 1

Hence, Option B is the correct answer.

8 0
3 years ago
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