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3 years ago

Solve by Substitution -8x-10y=12 -7x-10y=3

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

3 0

Answer:

Point Form:

(−9,6)

Equation Form:

x=−9,y=6

Step-by-step explanation:

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Given: m∠1 = 140°, find m∠6.

zavuch27 [327]

<h2>Answer:</h2>

Let m<6 be X

140° + X = 180°

X = 180° - 140°

X =40°

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3 years ago

How do you Calculate the mean,median and mode in grouped data.

Dmitrij [34]

Answer:

The mean:

data: 3,6,9,10

You first add all of the numbers together.

3+6+9+10= 28

There 4 numbers in the data set, so you divide 4 by the sum of all of the numbers.

28/4= 7

So the mean is 7.

The median:

data: 3,6,9,10

first put all of the numbers in numerical order.

3,6,9,10

Then you find the middle number in the data set.

3,6,(the middle number here),9,10

to find the middle number, do the mean of 6 and 9

The mean of 6 and 9 is 7.5

So, 7.5 is the median

another example: 3,4,7,9,13

The middle number is 7

so 7 is the median

The mode:

data: 3,6,9,10

The mode is the number that is repeated the most

in this data, there is no mode.

but in this data: 4,4,6,9,11

4 is the mode because it was repeated the most

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2 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

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Help! from usa test prep.

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Answer:

5 units

Step-by-step explanation:

If you look at AC that has 4 units and DE is close to 4 units but a little bigger by a unit

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3 years ago

Green's Flowers delivers standard flower

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Answer Greens charges less by 14.2%

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3 years ago

Solve by Substitution -8x-10y=12 -7x-10y=3​

Solve by Substitution -8x-10y=12 -7x-10y=3