From the second equation you can get [ x = 4 - y ], then substitude that for 'x' in the first equation, and finally, rearrange the first equation to read <u>x² - 4x + 16 = 0</u>
Don't even try to factor that quadratic equation. Go straight to the quadratic formula, and the two solutions you find are ...
<em>x = 2 + i 2√3</em> and <em>x = 2 - i 2√3</em> .