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3 years ago

What two numbers multiply to 16 and add to 4?

2 answers:

7 0

You said that (xy) = 16, and (x+y) = 4 .

From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
 x² - 4x + 16 = 0

Don't even try to factor that quadratic equation. Go straight
to the quadratic formula, and the two solutions you find are ...

 x = 2 + i 2√3
and
 x = 2 - i 2√3 .

Those are the two number that do what you want.

There are no real numbers that can do it.

Brilliant_brown [7]3 years ago

6 0

Xy=16
x + y = 4
-----------------

Solve those two equations for x and y.

The two numbers are: 2 - 2i sqr(3) and 2 + 2i sqr(3)

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Assume that y varies inversely with x. if y = 16 when x = 1/2, find y when x=32

MissTica

y varies inversely with x.

Example:

If we multiply x by 2 we need to divide y by 2 too.

So,

If y = 16 and x = 1/2, find y when x = 32

Lets see, from 1/2 to 32 e need to multiply 1/2 by 64, right? So let's divide 16 by 64.

16/64 = 8/32 = 4/16 = 2/8 = 1/4

So we can say that:

If y = 16 when x = 1/2, y = 1/4 when x = 32.

4 0

3 years ago

What’s the answer for -3(r-4)_>0

Zigmanuir [339]

Answer:

r<4

Step-by-step explanation:

-3(r-4)>0 step 1: distribute the -3

-3r+12>0 explain: -3 times r =-3r, -3 times -4 = 12

next, isolate the -3r by putting 12 on the other side

-3r+12>0 subtract 12 from both sides

-3r>-12 now, divide both sides by -3 (you have to flip the > because you are dividing by a negative) -12 divided by -3 is 4

so you should end up with r<4

8 0

3 years ago

Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a

Nimfa-mama [501]

Answer:

Step-by-step explanation:

When Riko left his house, Yuto was 5.25 miles along the path.

Average speed of Riko = 0.35 miles per minute

Average speed of Yuto = 0.25 miles per minute

First we will calculate the time in which Riko will catch Yuto on the track.

Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto

= 0.35 - 0.25

= 0.10 miles per minute

Now we this relative velocity tells that Riko is moving and Yuto is in static position.

By the formula,

Average speed = $\frac{Distance}{Time}$

0.10 = $\frac{5.25}{t}$

t = $\frac{5.25}{0.1}$

t = 52.5 minutes

Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.

So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5

Here time can not be less than zero because time can not be with negative notation. It will always start from 0.

3 0

4 years ago

Read 2 more answers

What is the general form of the equation for the given circle?

Westkost [7]

I think the answer is B or C

7 0

4 years ago

Please help me out!!!!!

Gnoma [55]

Valid because 3 x 3 is 9 :))

3 0

3 years ago