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Daniel [21]
3 years ago
11

Find the height of a parallelogram with an area of 56 and a base of 20.

Mathematics
1 answer:
qaws [65]3 years ago
6 0
The correct answer is 2.8
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Solve for k k/6 = 4/3
AURORKA [14]

Answer:

k = 8

Step-by-step explanation:

Given

\frac{k}{6} = \frac{4}{3} ( cross- multiply )

3k = 24 ( divide both sides by 3 )

k = 8

8 0
3 years ago
-4x - y = 24<br> Complete the missing value in the solution to the equation.<br> ( _,8)
Zinaida [17]

Answer:

(- 8, 8 )

Step-by-step explanation:

Given ( ?, 8 ) is a solution. To find x substitute y = 8 into the equation, then

- 4x - 8 = 24 ( add 8 to both sides )

- 4x = 32 ( divide both sides by - 4 )

x = - 8

Thus solution is (- 8, 8 )

5 0
3 years ago
How many pears would each person get if 14 pears are shared among 4 people
12345 [234]
To answer this, you would divide 14 pears / 4 people. The answer would be 3 1/2 pears per person.

3 0
2 years ago
Read 2 more answers
The coordinates of ∆ABC are A(-3, 2), B(5, 8) &amp; C(11, 0). Which type of triangle is ∆ABC? Select All that apply.
stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(5-(-3))^2+(8-2)^2}

AB=\sqrt{(8)^2+(6)^2}

AB=\sqrt{64+36}

AB=\sqrt{100}

AB=10

Similarly,

BC=\sqrt{(11-5)^2+(0-8)^2}

BC=\sqrt{(6)^2+(8)^2}

BC=\sqrt{36+64}

BC=\sqrt{100}

BC=10

And,

AC=\sqrt{(11-(-3))^2+(0-2)^2}

AC=\sqrt{(14)^2+(-2)^2}

AC=\sqrt{196+4}

AC=\sqrt{200}

AC=10\sqrt{2}

Two sides of the triangle are equal, i.e., AB=BC. So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

AB^2+BC^2=10^2+10^2

AB^2+BC^2=100+100

AB^2+BC^2=200

AB^2+BC^2=AC^2

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0
3 years ago
Is cos theta=cos(-theta)
saul85 [17]

Answer:

TRUE

Step-by-step explanation:

An even function is a function that satisfies that f(x) = f(-x). Also, we know that cosine is an even function, therefore cos(theta) equals cos(-theta).

4 0
2 years ago
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