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3 years ago

Find the height of a parallelogram with an area of 56 and a base of 20.

Mathematics

1 answer:

qaws [65]3 years ago

6 0

The correct answer is 2.8

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Please Help I Don't Understand!

asambeis [7]

Answer:

5.3

Step-by-step explanation:

Since they are similar triangles, we assume the ratio between AM/AN is equal to the ratio between MB/NC.
AM/AN = 6/8 = 3/4
If MB is 4
3/4 = MB/NC = 4/NC
3/4 = 4/NC

3NC = 16
NC = 16/3
16/3 = 5.333333

8 0

1 year ago

I will give Brainliest to First and Correct Answer. Can Somebody please help...I really need help and I am struggling.

igor_vitrenko [27]

Answer: B' (5,8), C' (3,1)

Step-by-step explanation:

You can use the points A' (-1,8) and A (-2,-3) to find how many units point A was translated.

-2 + 1 = -1

-3 + 11 = 8

Then, you simply add 1 to the x-values of points B and C and 11 to the y-values of points B and C to get B' (5,8), C' (3,1).

I hope this helps!

4 0

1 year ago

-(-3x-5)=7x what is x

konstantin123 [22]

Step-by-step explanation:

-(-3x-5)=7x

3x+5=7x

4x=5

x=5/4

5 0

2 years ago

Read 2 more answers

What is the value of n. 456 ÷ n = 4.56

sashaice [31]

456÷100=4.56

How to check your work: 456÷4.56=100

5 0

2 years ago

Read 2 more answers

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago