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pishuonlain [190]
3 years ago
11

Write the equation of a line that goes through points (5,6) and (2, 15).

Mathematics
1 answer:
Mila [183]3 years ago
8 0
Y=-3x+21
Is your answer! Please give me Brainly if correct
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PLEASE ANSWER!!! I WILL MARK YOU AS BRAINLIEST!!!
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Step-by-step explanation:

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Read 2 more answers
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

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3 years ago
Find the mean for the data set. 7, 6, 7, 7, 7, 4, 4, 6, 5, 5, 7
saul85 [17]

Answer:

5.909

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%202%5Cfrac%7B3%7D%7B4%7D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexFormula1" title=" 2\fra
docker41 [41]

let's firstly, convert the mixed fraction to improper fraction, and then subtract.


\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\cfrac{11}{4}-\cfrac{2}{3}\implies \stackrel{\textit{our LCD will be 12}}{\cfrac{(3)11-(4)2}{12}}\implies \cfrac{33-8}{12}\implies \cfrac{25}{12}\implies 2\frac{1}{12}

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3 years ago
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