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Vilka [71]
2 years ago
8

Need help with solving quadratics using the quadratic equation!

Mathematics
1 answer:
Charra [1.4K]2 years ago
3 0
You need to solve the following equation:
-0.5x^2 +36x -161 = 451

Set right side to 0
-0.5x^2 +36x -612 = 0

Multiply by -2 to get rid of decimal and leading neg coefficient.
x^2 -72x + 1224 = 0

Use quadratic formula:
a = 1, b = -72, c = 1224

x = \frac{-(-72) \pm \sqrt{(-72)^2 -4(1)(1224)}}{2(1)} \\  \\ x = \frac{72 \pm \sqrt{288}}{2} \\  \\ x = 27.51, 44.49

Therefore the min price to have 451 profit is $27.51
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grin007 [14]

Answer: 3x-4y+7=3y+1

Step-by-step explanation:

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4 0
3 years ago
You find 72 coins consisting only of nickels, dimes, and quarters, with a face value of $10.20. However, the coins all date from
Oliga [24]

Answer:

You have found 24 nickels.

Step-by-step explanation:

Let N be the number of nickles, D be the number of dimes and Q be the number of quarters. The number of coins and their face values are given by the following expressions, respectively:

N+D+Q=72\\0.05N+0.10D+0.25Q=10.20

As of now we have three variables and two expressions, the final expression needed to solve the linear system is given by the amount offered by the coin dealer:

10N+20D+15Q=1,060

Solving the linear system:

N+D+Q=72\\5N+10D+25Q=1,020\\10N+20D+15Q=1,060\\\\10N-10N+20D-20D+15Q-50Q=1,060-(2*1,020)\\-35Q=-980\\Q=28\\\\5N-10N+10D-10D+25Q-10Q=1,020-720\\-5N+15Q=300\\-5N=300-(15*28)\\N=24

You have found 24 nickels.

7 0
3 years ago
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