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irga5000 [103]
3 years ago
13

What is the value of y?

Mathematics
2 answers:
valentina_108 [34]3 years ago
3 0

Answer:

Step-by-step explanation:

(12,5)

Pavel [41]3 years ago
3 0
45*

For this we’ll only use the top most angles.
We have a straight across line, which is equal to 180*.
That is then cut in half making it a 90* shown by the box.
That makes the others side 90* before it’s cut.
Then it’s cut in half. 90/2=45

45*
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Can someone tell me the answer
Rzqust [24]

Answer:

A. 9/25

Step-by-step explanation:

There are a total of 25 T-shirts, which means that the denominator of the fraction is going to be 25 (which already rules out B and C). In the information they give us, they said that there are 9 red shirts. Therefore, the numerator will be 9. Our complete fraction is 9/25, or A.

I hope this helps! Have a lovely day!! :)

3 0
2 years ago
Read 2 more answers
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
3 years ago
Please help me with the following questions. Thanks in advance!!
Orlov [11]

Answer:

Step-by-step explanation:

Eight

590 = 1800 e^(-0.4t)     Divide by 1800

0.32778 = e^(-0.4t)       Put the value for e in the denominator.

0.32778 = 1 / e^(0.4t)   Notice the sign's gone. Multiply both sides by e^(0.4t)

0.32778 *e^(0.4t) = 1    Divide by 0.32778

e^(0.4t) = 3.0508          Take the natural log of both sides.

0.4t = 1.11542                 Divide both sides by 0.4

t = 2.78855

You should put this in the original equation to see if it checks. It does.

=============================

Nine

3^(3 - 3x) + 6 = 42         Subtract 6 from both sides

3^(3 - 3x) = 36               Take the log of both sides.

(3 - 3x) ln(3) = ln 36

(3 - 3x) *1.098612 = 3.58352   Divide by 1.098612

3 - 3x = 3.26186             Subtract 3 from both sides

- 3x = 0.26186                 Divide by - 3

x = - 0.087287    

4 0
3 years ago
Write the equation for the line that passes theough (-4 , 9) and is parallel to the given line
devlian [24]

Step-by-step explanation:

Equation is y = -3/4x + 12.

3 0
3 years ago
Use the simple interest formula to find the unknown quantity. I = prt I = $9 p = $450 r = 4% t =
Andreyy89

Answer:

1/2

just did this on edgenuity:)

4 0
3 years ago
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