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Brilliant_brown [7]
3 years ago
5

Write a linear eqaution for the point (3,-5) and slope=-4

Mathematics
2 answers:
ella [17]3 years ago
6 0
Y = -4x + 7
Have a great day:)
Citrus2011 [14]3 years ago
3 0

Answer:

y = -4x + 7

Step-by-step explanation:

You might be interested in
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
3 years ago
The area on a wall covered by a rectangular poster is 270 square inches. The length of the poster is 1.2 times longer than the w
forsale [732]

Answer:

Length = 18 in

Width = 15 in

Step-by-step explanation:

We have that the area of a rectangle is:

A = L * W

but L = 1.2 * W

A = 1.2 * (W ^ 2)

1.2 * (W ^ 2) = 270

(W ^ 2) = 270 / 1.2

W ^ 2 = 225

Therefore, W is equal to:

W = 225 ^ (1/2)

W = +/- 15, but only +15 makes sense

W = 15

Now for L:

L = 1.2 * 15

L = 18

A = 15 * 18 = 270 in ^ 2

4 0
3 years ago
Transformations<br>I need help on this worksheet please.
Neporo4naja [7]

Answer:

Step-by-step explanation:

Question 2

As far as I can see, you got it right. The general transformation for 90 ccw is

(x,y) ===> (-y, x)

What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.

The two tables are shown below.

Original

  • (1,4)
  • (1,2)
  • (3,2)
  • (3,5)

The transformed table is

  • (-4,1)
  • (-2,1)
  • (-2,3)
  • (-5,3)
  • (-4,1)    This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.

===========

Four

This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.

Original

  • (-4,3)
  • (0,3)
  • (-2,0)
  • (-4,3)  Here again, this is just to close the figure.

The transformed figure in red I think is

  • (4,-3)
  • (0,-3
  • (2,0)
  • (4,-3) And this closes the figure as well.

==========

Six

The diagram is on the right

Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.

  • (-3,0)
  • (-5,-2)
  • (-1,-2)

There is no closure.

Reflection

  • (3,0)
  • (5,-2)
  • (1,-2)

4 0
3 years ago
RESOLVER LOS SIGUIENTES SISTEMAS DE ECUACIONES APLICANDO EL METODO DE SUSTITUCION
kiruha [24]

Answer:

x = 1/2; y = 1/3

Step-by-step explanation:

2x + 3y = 2     Eq. 1

-6x + 12y = 1     Eq. 2

Eq. 1

2x + 3y = 2

2x = -3y + 2

x = -3/2 y + 1

Eq. 2

-6x + 12y = 1

De Eq. 1 sabemos que x = -3/2 y + 1

-6x + 12y = 1

-6(-3/2 y + 1) + 12y = 1

9y - 6 + 12y = 1

21y - 6 = 1

21y = 7

y = 7/21

y = 1/3

Eq. 1

2x + 3y = 2

2x + 3(1/3) = 2

2x + 1 = 2

2x = 1

x = 1/2

Respuesta: x = 1/2; y = 1/3

3 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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