Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
Answer:
Length = 18 in
Width = 15 in
Step-by-step explanation:
We have that the area of a rectangle is:
A = L * W
but L = 1.2 * W
A = 1.2 * (W ^ 2)
1.2 * (W ^ 2) = 270
(W ^ 2) = 270 / 1.2
W ^ 2 = 225
Therefore, W is equal to:
W = 225 ^ (1/2)
W = +/- 15, but only +15 makes sense
W = 15
Now for L:
L = 1.2 * 15
L = 18
A = 15 * 18 = 270 in ^ 2
Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
===========
Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
==========
Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
There is no closure.
Reflection
Answer:
x = 1/2; y = 1/3
Step-by-step explanation:
2x + 3y = 2 Eq. 1
-6x + 12y = 1 Eq. 2
Eq. 1
2x + 3y = 2
2x = -3y + 2
x = -3/2 y + 1
Eq. 2
-6x + 12y = 1
De Eq. 1 sabemos que x = -3/2 y + 1
-6x + 12y = 1
-6(-3/2 y + 1) + 12y = 1
9y - 6 + 12y = 1
21y - 6 = 1
21y = 7
y = 7/21
y = 1/3
Eq. 1
2x + 3y = 2
2x + 3(1/3) = 2
2x + 1 = 2
2x = 1
x = 1/2
Respuesta: x = 1/2; y = 1/3
Given:


To find:
The value of
.
Solution:
We have,


Using properties of log, we get
![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute
and
.



Therefore, the value of
is
.