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3 years ago

12

select all the correct answers. Consider the function f and function G. f(x) = ln x, g(x)= -5 ln x. How does the graph of functi

on g compare with the graph of function f? NO LINKS!!

1 answer:

Kaylis [27]3 years ago

6 0

f(x)=ln(x){Attachment 1}
g(x)=-5ln(x){Attachment 2}

Option C and B are correct

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A quadrilateral does have 4 side

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3 years ago

At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T

OLEGan [10]

Answer:

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

$\text{Area of circle}=\pi r^2$ , where r represents radius of the circle.

$\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2$

$\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2$

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

Therefore, the exact area of the side walk is $40 \pi\text{ m}^2$

To find the approximate area of side walk let us substitute pi equals 3.14.

$\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Therefore, the approximate area of the side walk is $125.6\text{ m}^2$ .

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3 years ago

-4xy if x is 4 and y is -5

Mars2501 [29]

Answer:

-5

Step-by-step explanation:

$-4xy$

$-4+4-5$

$-5$

Hope this helped! :)

P.S. You might wanna practice PEDMAS for it is in this equation. ;)

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Step-by-step explanation:

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