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2 years ago

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Jina must choose a number between 55 and 101 that is a multiple of 3, 6, and 9. Write all the numbers that she could choose.

1 answer:

kupik [55]2 years ago

8 0

Answer:

Join Zoom Meeting

Meeting ID: 385 546 8984

Passcode: icecream4

Step-by-step explanation:

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Vanessa wants to purchase a new cell phone plan. The two plans from which she can choose are shown below. Vanessa used the syste

user100 [1]

Answer:

2. 325 minutes.

Step by step explanation:

We will substitute our given number of minutes in our both equation one by one to find the correct option.

1. Let us substitute m= 775 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 775$

$CA=22+100.75=122.75$

$CB=44+0.09(m-100)$

$CB=44+0.09(775-100)$

$CB=44+0.09\cdot675$

$CB=44+60.75=104.75$

$104.75\neq122.75$

We can see that both plans have different costs , therefore, 1st option is incorrect.

2. Let us substitute m= 325 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 325$

$CA=22+42.25=64.25$

$CB=44+0.09(m-100)$

$CB=44+0.09(325-100)$

$CB=44+0.09\cdot 225$

$CB=44+20.25=64.25$

$64.25=64.25$

When Vanessa has used the phone for 325 minutes, the cost for Plan A and the cost for Plan B will both be $64.25.Therefore, 2nd option is correct choice.

3. Let us substitute m= 32.5 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 32.5$

$CA=22+4.225=26.225$

$CB=44+0.09(m-100)$

$CB=44+0.09(32.5-100)$

$CB=44+0.09\cdot -67.5$

$CB=44-6.075=37.925$

$37.925\neq26.225$

4. Let us substitute m= 764 in both equations.

$CA=22+0.13m$

$CA=22+0.13\cdot 764$

$CA=22+99.32=121.32$

$CB=44+0.09(m-100)$

$CB=44+0.09(764-100)$

$CB=44+0.09\cdot 664$

$CB=44+59.76=103.76$

$121.32\neq103.76$

Therefore, 4th option is incorrect.

3 0

3 years ago

Is this nonlinear?<br><br><br><br><br><br><br><br><br><br><br><br><br><br> S

musickatia [10]

Answer: it seems to be Liner

Step-by-step explanation:

Has a Constant rate

7 0

3 years ago

Read 2 more answers

42. Which of the following is TRUE about the princal square riot

kherson [118]

Answer:

a. always positive

Step-by-step explanation:

Alex learning?

5 0

3 years ago

how do you have a reflection in the x axis, if the shape is already partially in the third and second quadrent of the graph

IgorLugansk [536]

Its a reflection over an x-axis, whats "positive" goes "negative" and whats "negative" goes "positive" with respect to y.

If a shape $S$ is a subset (made of $P_2\cup P_3$ of quadrants $Q_2,Q_3$ then the part $P_2$ that lies in the second quadrant gets mapped to $Q_3$ and part $P_3$ that lies in third quadrant gets mapped to $Q_2$

Hope this helps.

8 0

3 years ago

What is the difference? Negative 6 minus (11)

aleksklad [387]

Answer:

-17

Step-by-step explanation:

-6-11=-17

4 0

3 years ago