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abruzzese [7]
3 years ago
14

A candidate taking a mathematics paper is told to answer 5 of the 7 questions in section A, and 3 questions from the 5 options(e

ach option consists of 3 questions) in Section B, where not more than 2 questions from the same option can be chosen. Assuming that he answers 8 questions altogether, find how many different combinations of questions he could attempt.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
4 0
He could find 15 different combinations of questions I think. This question is confusing.
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Translate the following expression to an equation in terms of p​: "151.8​​ is what percent of 69​​?"
Lostsunrise [7]

The statement "151.8​​ is what percent of 69​​ is expressed as 0.69p =  151.8

<h3>Equations and expressions</h3>

Equations are expressions separated by an equal sign. Words can be translated to equations.

Let the unknown variable be "p". If p percent of 69is 151.8, this is expressed as;

p% of 69 = 151.8

Convert to decimals

p/100 * 69 = 151.8

0.01p * 69 = 151.8
0.69p =  151.8

Hence the statement "151.8​​ is what percent of 69​​ is expressed as 0.69p =  151.8

Learn more on equations here: brainly.com/question/2972832

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2 years ago
Hey lads could you please check out my channel on you.tube please leave a like and subscribe it would help a lot much love stay
Sergio039 [100]

Answer:

yes if u give points lol

Step-by-step explanation:

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How many times does 28 go into 7010000
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an projectile is launched upward with a velocity of 256 feet per second from the top of a 35 foot structure. what is the maximum
Anettt [7]

1052.64 feet

Step-by-step explanation:

Step 1:

Given,

The projectile is launched upward with a velocity of 256 feet per second

The height of the structure is 35 foot.

Step 2 :

The velocity becomes 0 at the highest point.

The equation of motion is v² = u² +2as

where

v represents the final velocity

u represents the initial velocity

a represents the acceleration due to gravity

s is the height

Step 3:

Here  we have

u = 256 feet/sec

v = 0

a = -32.2 feet/sec²

Substituting in the above equation, we have

0 = 256² + 2 *(-32.2) *s

=>  -64.4 s = -65536

= > s = 65536/64.4 = 1017.64 feet

Hence the projectile travels 1017.64 feet from the top of the structure. Since the height of the structure is given as 35 feet, the maximum height attained by the projectile is 1017.64 +35 = 1052.64 feet

8 0
3 years ago
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