Answer:
Three equivalent ratios of 
are 
, 
and 
.
Step-by-step explanation:
We are given a fraction .
We need to find the three equivalent ratios/fractions of .
The common factor of 14 and 2 is 2.
So, dividing top and bottom by 2, we get
14÷2 = 7 and 2÷2 that is .
Multiplying fraction by a common number 3 in top and bottom, we get
7 × 3 = 21
1 × 3 = 6
So, we get another equivalent fraction 
.
Multiplying fraction by a common number 3 in top and bottom, we get
7 × 4 = 28
1 × 4 = 4
So, we get another equivalent fraction 
.
Therefore, three equivalent ratios of are , and .
Super easy. Take the function, and replace X with Y and Y with X. For example, if Y=12/x, then the inverse would be X=12/Y. Now solve for Y, so XY=12, the Y=12/x.
Answer:
the radius of the circle is 6cm
Step-by-step explanation:
the area of a circle is given to be = 36πcm²
radius of the circle = ?
to find the radius of the circle lets start by applying the formula for finding the area of a circle.
area of a circle = πr²
36πcm² = πr²
36π = πr²
divide both sides by π
36π/π = πr²/π
36 = r²
to get the value of r we are going to look for a way of getting rid of the square on "r" by squaring 36
r² = 36
r =√36
r = 6cm
therefore the radius of the circle is 6cm
The first one is correct because that one shows how many times you drank milk today but the rest show how many times you drank milk yesterday.
Answer:
4. -2s^9
7. 8b^10
Step-by-step explanation:
First, focus on the number part of the expression. For 4), multiply -2 x -1 x -1 = -2. Then, look at the exponents. When you're multiplying exponents with the same base (in number 4, the base is s), you can add the exponents.
2+3+4 = 9; which makes it s^9. Multiply -2 x s^9, which gives you -2s^9.
Same thing for 7). Multiply all the numbers first. this gives you 8. (Remember two negatives equals a positive). Add all of the exponents of b together, which gives you 10. (when a variable has no exponent, it means that the exponent is 1.) Multiplying 8 and b^10 should give you 8b^10.
It may help to brush up on exponent rules and sign rules.
