Question

Hailey is designing a new board game, and is trying to figure out all the possible

Answer 1

Given:

Numbers on die = 1, 2, 3, 4

Colors on board = Red, Green, Blue, Orange (equal sized sections)

To find:

The number of different possible outcomes are there if she rolls a fair die in the board.

Solution:

According to the given information,

The total possibilities for numbers = 4

Total possibilities for colors = 4

Total possibilities = Possibilities for number × Possibilities for colors

                             = $4\times 4$

                             = $16$

So, total 16 possible outcomes are there if she rolls a fair die in the board.

Let Red=R, Green=G, Blue=B, Orange=O, then list of total possible outcomes is:

{1R,1G,1B,1O,2R,2G,2B,2O,3R,3G,3B,3O,4R,4G,4B,4O}

Therefore, the total possible outcomes are 16 and the lies of outcomes is {1R,1G,1B,1O,2R,2G,2B,2O,3R,3G,3B,3O,4R,4G,4B,4O}.