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Vika [28.1K]
3 years ago
10

On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snoho

mish River below. The swimmers stepped off the bridge, and I estimated that they hit the water 1.5 s later. (a) How high was the bridge
Mathematics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer: the bridge is 11.025 m high

Step-by-step explanation:

Given that;

Time taken to hit the water t = 1.5 sec

height of bridge = ?

lets take a look at the equation of motion;

y(t) = y₀ + (1/2)at²

with initial velocity zero and we know that acceleration due to gravidity is 9.8m/s

we substitute

y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²

y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²

y(1.5) = 11.025 m

Therefore, the bridge is 11.025 m high

 

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The probability that your call to a service line is answered in less than 30 seconds is 0.85. Assume that your calls are indepen
aev [14]

Answer:

a) 0.1720

b) 0.8298

c) 19

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.85

(a) If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12.

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.85)^{9}.(0.15)^{3} = 0.1720

(b) If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.85)^{16}.(0.15)^{4} = 0.1821

P(X = 17) = C_{20,17}.(0.85)^{17}.(0.15)^{3} = 0.2428

P(X = 18) = C_{20,18}.(0.85)^{18}.(0.15)^{2} = 0.2293

P(X = 19) = C_{20,19}.(0.85)^{19}.(0.15)^{1} = 0.1368

P(X = 20) = C_{20,20}.(0.85)^{20}.(0.15)^{0} = 0.0388

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1821 + 0.2428 + 0.2293 + 0.1368 + 0.0388 = 0.8298

(c) If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.85 = 18.7

The nearest integer to 18.7 is 19.

7 0
3 years ago
60=F(15) <br><br> Please solve this and show work, please
Lubov Fominskaja [6]

Answer:

f = 4

Step-by-step explanation:

60= 15f

divide both side by 15

f = 4

3 0
3 years ago
36 + 120 : 12-63<br> What's this answer?
NeTakaya

Answer:

Step-by-step explanation:

36 + 120: 12-63

156 :  51

GCF of both sides are three. Divide both sides by three.

52:17

5 0
3 years ago
Which is the average rate of change over the interval [0, 10]? Hint: Find rate of change for both equations
GaryK [48]
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8 0
3 years ago
Brent purchased a used vehicle that depreciates under a straight-line method. The initial value of the car is $7500, and the sal
Ilia_Sergeevich [38]
Let the value of the vehicle be described by the equation
V = a + bx
where x =  number of years since purchase
a,b are constants.

When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500

When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000

The equation is
V = 7500 - 1000x

The slope of this equation is the depreciation rate, and it is -$1000 per year.

Answer: $1000 depreciation per year.

5 0
3 years ago
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