Answer:
one ton :)
Step-by-step explanation:
Answer:
RGDF
RGDF
Step-by-step explanation:
rgdf
rgdf
RGDF
F(4)=6(4) +3
= 24+3=27
F(4)=27.
Answer:
The first and third quartiles were calculated incorrectly. Also, this means the inter quartile range is incorrect.
Step-by-step explanation:
The first quartile is going to be the median of the lower half of the data set {89, 93, 99, 110} this median is (93+99)/2, or 96.
The third quartile can be calculated the same way with the data set {135, 144, 152, 159} This gives us 148 as the third quartile.
Lastly, the interquartile range is just the difference between the first and third quartiles, which is 52.
I'm going to assume that your function is f(x) = 1 + x^2 (NOT x2).
I suspect you're trying to estimate the "area under the curve of f(x) = 1 + x^2. You need to use this or a similar description to explain what you're doing.
Also, you need to specify whether you want "left end points" or "right end points" or "midpoints." Again I must assume you want one or the other (and will assume that you meant "left end points").
First, let's address the case n=3. You must graph f(x) = 1 + x^2 between -1 and +1. We will find the "lower sum," using "left end points." The 3 x-values are {-1, -1/3, 1/3}. Evaluate the function f(x) = 1 + x^2 at these 3 x-values. Keep in mind that the interval width is 2/3.
The function (y) values are {0, 2/3, 4/3}.
Sorry, Michael, but I must stop here and await clarification from you regarding what you've been told to do in this problem. Otherwise too much guessing (regarding what you meant) is necessary. Please review the original problem and ensure that you have copied it exactly as presented, and also please verify whether this problem does indeed involve estimating areas under curves between starting and ending x-values.
