The parameter of the study's population is the 80% of all customers who shopped in the chain's stores that were interested in the home delivery service.
Population parameter is defined as any summary number that describes the entire population. It can be an average or a percentage/
The 1,000 customers that were surveyed are the sample of the population. They basically represent the population of the chain's customers.
Complimentary angles will add up to 90 degrees
x + y = 90
x = 2y
2y + y = 90
3y = 90
y = 90/3
y = 30......this is one angle
x = 2y
x = 2(30)
x = 60.....this is ur other angle
and ur larger angle is 60 degrees
Answer:
Yes, we reject the auto maker's claim.
Step-by-step explanation:
H0 : μ ≥ 20
H1 : μ < 20
Sample mean, xbar = 18 ;
Sample size, n = 36
Standard deviation, s = 5
At α = 0.01
The test statistic :
(xbar - μ) ÷ s /sqrt(n)
(18 - 20) ÷ 5/sqrt(36)
-2 /0.8333333
= - 2.4
Pvalue from test statistic : Pvalue = 0.00819
Pvalue < α
0.00819 < 0.01
Hence, we reject the Null
Answer:
83.25
Step-by-step explanation:
add all the numbers and divide by 8. 666/8 = 83.25
Answer:
Region D.
Step-by-step explanation:
Here we have two inequalities:
y ≤ 1/2x − 3
y < −2/3x + 1
First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.
And we have that:
y ≤ 1/2x − 3
y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.
Now let's look at the other one:
y < −2/3x + 1
y = (-2/3)*x + 1
is the dashed line in the graph.
And we have:
y < −2/3x + 1
So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.
The regions below the dashed line are region A and region D.
The solution for the system:
y ≤ 1/2x − 3
y < −2/3x + 1
Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.
Then the correct option is region D.
