Question

give the equation of a line that goes through the point (-4,-1) and is parallel to the line -3x+5y=-10​

Answer 1

Answer:

$y=\frac{3}{5} x+\frac{7}{5}$

Step-by-step explanation:

1) the equation of the given line in the slope-interception form is:

y= 3/5 x -2;

the equation of the required line is

y=slope*x+i;

2) if the required line is parallel to the given one, it means, the value of its slope is the same, it means 3/5;

then the equation of the required line is

y=3/5*x+i;

3) if the point (-4;-1) belongs to the required line, then it is possible to substitute its coordinates into the equiation of the required line

-1= 3/5*(-4)+i;

4) it is possible to calculate the value of 'i':

i=7/5;

5) if slope=3/5, i=7/5, then the required equation of the line in slope-interception form is:

$y=\frac{3}{5} x+\frac{7}{5}.$