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3 years ago

8

31 Two identical umber cubes are shown in the picture. The edge length of these number cubes was the combined volume of the two

number cubes in cubic centimeters CS

1 answer:

emmainna [20.7K]3 years ago

5 0

Answer:

I really don’t no

Step-by-step explanation:

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What is -7(w+6)^2+21=0.

adoni [48]

After solving for w using inverse operations, w would have to equal 5.74 to make this equation true.

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3 years ago

Complete the equation. (x-2)(x^2 + 2x + 4) = ( , )

yanalaym [24]

Answer:

Step-by-step explanation:

x(x² + 2x + 4)-2((x² + 2x + 4)

x³+2x²+4x -2x²-4x-8

x³-8

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3 years ago

How do you do this question?

Step2247 [10]

Answer:

D

Step-by-step explanation:

$f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D$

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3 years ago

Lines m and n are parallel solve for the following values of x. Tell which theorem you used.

nevsk [136]

Answer:

x=60°

Step-by-step explanation:

angle 135° and (2x+15)° are corresponding and thus are equal

Therefore (2x+15)°=135°

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3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, <u><em>test statistics</em></u> = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

4 years ago