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2 years ago

8

31 Two identical umber cubes are shown in the picture. The edge length of these number cubes was the combined volume of the two

number cubes in cubic centimeters CS

1 answer:

emmainna [20.7K]2 years ago

5 0

Answer:

I really don’t no

Step-by-step explanation:

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What is the solution of the equation 1.6m - 4.8 = -1.6m

Flauer [41]

Solve for m:
1.6 m - 4.8 = -1.6 m

Add 1.6 m to both sides:
1.6 m + 1.6 m - 4.8 = 1.6 m - 1.6 m

1.6 m - 1.6 m = 0:
1.6 m + 1.6 m - 4.8 = 0

1.6 m + 1.6 m = 3.2 m:
3.2 m - 4.8 = 0

Add 4.8 to both sides:
3.2 m + (-4.8 + 4.8) = 4.8

4.8 - 4.8 = 0:
3.2 m = 4.8

Divide both sides of 3.2 m = 4.8 by 3.2:
(3.2 m)/3.2 = 4.8/3.2

3.2/3.2 = 1:
m = 4.8/3.2

4.8/3.2 ≈ 1.5:
Answer: m ≈ 1.5

6 0

3 years ago

zimovet [89]

Answer:

m less then 5

Step-by-step explanation:

its telling you itw no less than 5 so you want to use a less than symbol.

7 0

3 years ago

Greg has to carry 191 apples from a farm to the market. how many baskets will need, given that each basket can hold 42 apples?

soldi70 [24.7K]

191 / 42 = 4.5.....so Greg is gonna need 5 baskets....but the last basket is only gonna be half full.

8 0

3 years ago

Yul has lunch at a resterant if his bill was $14.50 and yul wants to leave a 20% tip what is the amount he should leave for the

Triss [41]

14.50 times 0.20 = 2.9

He would give a $2.90 as a tip of 20% from a bill of $14.50

4 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago