Answer:
4 / 3
Step-by-step explanation:
tan x = opposite / adjacent
tan x = AB / AC
tan x = 4 / 3
{ x = theta ]
9514 1404 393
Answer:
Rotation 90° CCW
Step-by-step explanation:
Note that Figure 1 has a small appendage off the larger rectangle. That appendage is pointing East (to the right).
In Figure 2, that same appendage is pointing North (up).
If you are facing East and you want to face North, you will find that you need to turn 90° in the counterclockwise direction. That is the transformation that was done here:
rotation 90° CCW about the origin
Answer:
B. 88°
Step-by-step explanation:
In a properly drawn circle graph, the central angle is proportional to the size of the number being displayed. Here, 122 of 500 selected football. Since the total angle of a circle is 360°, that fraction is ...
(122/500)×360° = 87.84° ≈ 88°
Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of is
Generally since the sample proportion is not given we will assume it to be
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=>
Generally the margin of error is mathematically represented as
Generally if the level of confidence increases, the critical value of 
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
