Answer:
The answer is 144
Step-by-step explanation:
19/38 = 1/2 (divided top and bottom by 19)
so
34 X 19/38
= 34 X 1/2
= 34/2
= 17/1
Answer
17/1 (or 17)
Answer:
2x + 10
Step-by-step explanation:
To expand (using the distributive property) <u>multiply</u> the number outside the bracket i.e. in this case '2', with the <u>values inside the brackets</u>.
So multiply '2' and 'x' and '2' and 5' and add or subtract on basis of whether the second value is positive or negative.
So
2(x + 5)
= (2*x)+(2*5)
=2x+10
<em>extention note:</em> <u>be careful</u> when the symbol within the equation within the brackets is a subtraction because it implies that the second value would instead be a negative number and should be treated as such.
an example
2(x-5)
= (2*x)+(2*-5)
=2x -10
Anyhow, I hope this helped!
Answer:
Therefore the value of EC is 13 unit.
Step-by-step explanation:
Given:
ABCD is a Rectangle
EC = 6x + 1
AE = x +11
To Find:
EC = ?
Solution:
ABCD is a Rectangle .........Given
Diagonal of Rectangle Bisect each other. .......Property of Rectangle
Substituting the values we get'
Substituting 'x' in EC we get
Therefore the value of EC is 13 unit.
Answer:
We <em>fail to reject H₀ </em>as there is insufficient evidence at 0.5% level of significance to conclude that the mean hours of TV watched per day differs from the claim.
Step-by-step explanation:
This is a two-tailed test.
We first need to calculate the test statistic. The test statistic is calculated as follows:
Z_calc = X - μ₀ / (s /√n)
where
- X is the mean number of hours
- μ₀ is the mean that the sociologist claims is true
- s is the standard deviation
- n is the sample size
Therefore,
Z_calc = (3.02 - 3) / (2.64 /√(1326))
= 0.2759
Now we have to calculate the z-value. The z-value is calculated as follows:
z_α/2 = z_(0.05/2) = z_0.025
Using the p-value method:
P = 1 - α/2
= 1 - 0.025
= 0.975
Thus, using the positive z-table, you will find that the z-value is
1.96.
Therefore, we reject H₀ if | Z_calc | > z_(α/2)
Thus, since
| Z_calc | < 1.96, we <em>fail to reject H₀ </em>as there is insufficient evidence at 0.5% level of significance to conclude that the mean hours of TV watched per day differs from the claim.
