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2 years ago

What are the domain and range of f(x) = 4x – 8?

Mathematics

1 answer:

Andrej [43]2 years ago

8 0

F(x) = mx + b represent the straight line. If m ≠ 0 then the domain and the range of that function are real number.

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PLZZZZ HELP The Lakeview city council is considering two different plans to help reduce the amount of pollution in the city. Pla

sdas [7]

1. The two equations follow the slope-intercept form which y=mx + b. They have the same y-intercept which is equal to 900.

2. Suppose x= 10
Plan Alpha: y=-7x+900=-7(10)+900=830
Plan Foxtrot: y = -17x+900 = -17(10)+900=730

Between the 2 plans, the lower value is 730. Plan Foxtrot is better for reduction of pollution.

3. The city council should choose Plan Foxtrot because the reduction of pollution is much greater. Their goal would be reached faster if they go with faster reduction of pollution.

5 0

2 years ago

when simplifying the expression y=(2x(x-3)(x-3))/(x-1)(x-3) do all of the x-3 s get cancelled or just one in the numerator and o

Ksju [112]

Answer:

Just one of the ones in the numerator and the one in the denominator

Step-by-step explanation:

7 0

3 years ago

A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the

Stells [14]

Answer:

$\frac{5}{3}$ in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box= $L\times B\times H$

Substitute the values then we get

Volume of box=V(x)= $(8-2x)(15-2x)x=(15x-2x^2)(8-2x)$

$V(x)=120x-30x^2-16x^2+4x^3$

$V(x)=4x^3-46x^2+120x$

Differentiate w.r.t x

$V'(x)=12x^2-92x+120$

$V'(x)=0$

$12x^2-92x+120=0$

$3x^2-23x+30=0$

$3x^2-18x-5x+30=0$

$3x(x-6)-5(x-6)=0$

$(x-6)(3x-5)=0$

$x-6=0\implies x=6$

$3x-5=0\implies x=\frac{5}{3}$

Again differentiate w.r.t x

$V''(x)=24x-92$

Substitute x=6

$V''(6)=24(6)-92=52>0$

Substitute x=5/3

$V''(5/3)=24(5/3)-92=-52$

Hence, the volume is maximum at x= $\frac{5}{3}$

Therefore, the side of the square , $x=\frac{5}{3}$ in cutout that gives the box the largest possible volume.

5 0

2 years ago

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus

Ksivusya [100]

Given:

The given equation is:

$16-3p=\dfrac{2}{3}p+5$

To find:

The value of p.

Solution:

We have,

$16-3p=\dfrac{2}{3}p+5$

Multiply both sides by 3.

$3(16-3p)=3\left(\dfrac{2}{3}p+5\right)$

$48-9p=2p+15$

Isolating the variable terms, we get

$48-15=2p+9p$

$33=11p$

Divide both sides by 11, we get

$\dfrac{33}{11}=p$

$3=p$

Therefore, the required solution is $p=3$ .

7 0

2 years ago

How do you rearrange fractions

almond37 [142]

For ex:

U have 4/8 - 6/2 u would probably have to use KCF- Keep Change Flip
So then it’ll be 4/8 + 2/6
U kept the 4/8 then u changed the subtraction to addition and u flipped the 2 to the numerator and the 6 denominator.
Idk my dude this is what I can think of

4 0

3 years ago