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3 years ago

Write the equation in slope intercept form ?

Mathematics

2 answers:

Kamila [148]3 years ago

7 0

Answer: first Option

Work: So, Slope Intercept form is y=mx+b, so, we need to get the 13x Away from there. So, we subtract 13x from there, and we get -11y = 13x - 12. To get it to y, we divide 13x - 12 by -11. So the new equation is y = -13/11x + 12/11

QveST [7]3 years ago

6 0

Answer:

The answer is B.

Step-by-step explanation:

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I do this do y'all can get extra point and complete challenges! What is 3 + 3

Wittaler [7]

Answer:

Step-by-step explanation:

3 + 3 = 6

5 0

3 years ago

Read 2 more answers

What are the exact steps to solve for the x-intercepts of f(x)= −4x2 + 4x + 8? What about −9 = x2 + 6x? Please explain thoroughl

victus00 [196]

Answer:

x-intercepts: (-1, 0) and (2, 0)

x-intercept: (-3, 0)

Step-by-step explanation:

Given quadratic function:

$f(x)=-4x^2+4x+8$

The x-intercepts of a quadratic function are the points at which the curve crosses the x-axis ⇒ when y = 0

Therefore, to find the x-intercepts of the given function, set the function to zero:

$\implies -4x^2+4x+8=0$

Factor out -4:

$\implies -4(x^2-x-2)=0$

Divide both sides by -4

$\implies x^2-x-2=0$

Rewrite the middle term as -2x + x:

$\implies x^2-2x+x-2=0$

Factor the first two terms and the last two terms separately:

$\implies x(x-2)+1(x-2)=0$

Factor out the common term (x - 2):

$\implies (x+1)(x-2)=0$

Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}(x+1) & = 0 & \quad \textsf{ or } \quad \quad (x-2) & = 0\\\implies x & = -1 & \implies x & = 2\end{aligned}$

Therefore, the x-intercepts are (-1, 0) and (2, 0).

---------------------------------------------------------------------------------------

Given quadratic equation:

$-9 = x^2 + 6x$

Add 9 to both sides:

$\implies x^2+6x+9=0$

Rewrite the middle term as 3x + 3x:

$\implies x^2+3x+3x+9$

Factor the first two terms and the last two terms separately:

$\implies x(x+3)+3(x+3)=0$

Factor out the common term (x + 3):

$\implies (x+3)(x+3)=0$

$\implies (x+3)^2=0$

Square root both sides:

$\implies (x+3)=0$

Solve for x:

$\implies x=-3$

Therefore, the x-intercept is (-3, 0).

As the function has a repeated factor (multiplicity of two), the curve will touch the x-axis at (-3, 0) and bounce off.

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2 years ago

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uysha [10]

2-9/9 ion kno what this is sorry

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3 years ago

Enter the value for x that makes the equation -3(x-4)+x=2x true.

Norma-Jean [14]

Answer:

x = 3

Step-by-step explanation:

Simplify the equation to -3x + 12 + x = 2x, and then to -2x + 12 = 2x. Now you have to make the x values on one side so now you are left with 12 = 4x, so you just simplify by dividing 12 by 4. The answer is 3 = x.

7 0

3 years ago

Help meeeeee pleaseeeeeee

marusya05 [52]

Roy is correct. When you multiply fractions, you multiply the numerator of one fraction and the other numerator of the other fraction, and vice versa for denominator.
7 x 3 = 21 (Numerators)
——- —-
3 x 8 = 32 (Denominators)

I hope this helped!

3 0

3 years ago