The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
IAIA IAiO IBIB IBiO IAIB iOiO
These are the blood types: A, A, B, B, AB, and O, respectively.
Since both A and B are dominant to O, which is recessive, they share the trait when both expressed (type AB).
This is called [B. Codominance.]
Answer:
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Explanation:
if u mean something else, provide context and ill leave a comment with the correct answer
Answer:
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