Answer: There is presence of tumor.
Explanation: The adhesion of cells to extracellular matrix (EMC) through integrins ( cell-EMC binding molecules, which are collagens, laminins and fibronectin) causes the activation of kinases in the cytoplasm.
However, kinanes helps in controlling the epithelial cell differentiation and upholding the epithelial tissues. This is done by the addition of phosphate groups to a substrate protein which is termed Protein phosporylation. Then, the kinases direct the affairs of the cell and it's activities. For example, it determines the cell division, anabolic and catabolic activities of the cell, movement of ions between the cell and it's environment (signal transduction), protein functions and etc.
Conclusively, since the activities of the cell like cell division and protein functions is dictated by the kinase, reduction in cell division that gave rise to rapid growth is put on hold. Hence, the tumor is been suppressed.
Note: the binding of cell-EMC is regulated by Transforming Growth Factor (TGF) β.
Answer:
B. they bring cold , polar winds to the equator
The right option is; extreme traits
Disruptive selection events select for extreme traits.
Disruptive selection is a type of natural selection in which organisms with extreme traits are favored (such as in reproduction) over organisms with intermediate traits. This type of selection results in increased traits differences with increase in frequency of the alleles for the extreme traits. Disruptive selection can lead to the digression in a species line.
Phenotypes are the way the animal looks, the Genotypes are the the genetic makeup: like BB or Bb or bb
Answer:
45 g of the solid Tris will be dissolved in 2.5 liters of water.
Explanation:
Recall that:
<em>Number of moles = molarity x volume</em>
Hence, number of moles of Tris present in 2.5 liters, 150 mM solution:
= 150/1000 x 2.5 = 0.375 moles
Also, recall that:
<em>No of moles of substance = mass/molar mass.</em>
Hence, mass of 0.375 moles substance:
= no of moles of the substance x molar mass of the substance.
= 0.375 x 120 = 45 g.
Therefore, in order to prepare 2.5 liters, 150 mM of an aqueous solution of Tris, 45 g of the solid Tris will be dissolved in 2.5 liters of water.
