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leva [86]
3 years ago
15

Please help!! Needed ASAP!!

Mathematics
1 answer:
yarga [219]3 years ago
3 0

Answer and Explanation:

If, on the other hand, the graph "flexes" or "flattens out" to some degree when it goes to cross the axis, then the zero is of a higher multiplicity; that is, it'll be of multiplicity three, five, or higher.

When a graph doesn't start at 0, it means that the graphs before it is not shown.

For number 4, I'd suggest Graph 3.

For number 3, I'd suggest graph 1.

For number 5, Write something along the lines of "Graph 2 does not show the car stopping slowly, it stops suddenly. Then it starts going really fast and stops suddenly again."

I hoped this helped.

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Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).
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The equation of the line is y=\frac{1}{4}x-\frac{29}{7}

Explanation:

The equation of the line is perpendicular to y=-14 x-8

The equation is of the form y=mx+b where m=-14

<u>Slope:</u>

The slope of the perpendicular line can be determined using the formula,

m_1 \cdot m_2=-1

-14 \cdot m_2=-1

       m_2=\frac{1}{14}

Thus, the slope of the line is m=\frac{1}{14}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the slope m=\frac{1}{14} and the point (2,-4), we get,

y+4=\frac{1}{14}(x-2)

Simplifying, we get,

y+4=\frac{1}{14}x-\frac{1}{7}

     y=\frac{1}{14}x-\frac{1}{7}-4

     y=\frac{1}{4}x-\frac{29}{7}

Thus, the equation of the line is y=\frac{1}{4}x-\frac{29}{7}

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Step-by-step explanation:

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