All categories

3 years ago

X+y=10, y+z=14,x+y+z=18. Find the values of x, y, and z

Mathematics

2 answers:

den301095 [7]3 years ago

4 0

Answer:

x = 4, y = 6, z = 8

Step-by-step explanation:

x + y = 10

y + z = 14

x + y + z = 18

z = (x + y + z) - x - y

= 18 - 10

z = 8

y = (y + z) - z

= 14 - 8

y = 6

x = (x + y) - y

= 10 - 6

x = 4

iragen [17]3 years ago

3 0

x = 4

y = 6

z = 8

those are the answers

You might be interested in

Please help I need the answer to this

Scrat [10]

Answer:

Step-by-step explanation:

Substitute 2 for t in your formula

5 0

2 years ago

Read 2 more answers

Geometry

trapecia [35]

Answer:

EF = 8

Step-by-step explanation:

The following data were obtained from the question:

EF = 2x

FG = 8

EG = 4x

EF =?

To obtain the value of EF, we shall first, obtain the value of x. This can be obtained as follow:

EG = EF + FG

EF = 2x

FG = 8

EG = 4x

4x = 2x + 8

Collect like terms

4x – 2x = 8

2x = 8

Divide both side by 2

x = 8/2

x = 4

Therefore, the value of x is 4.

Finally, we shall determine the the value of EF as follow:

EF = 2x

x = 4

EF = 2x

EF = 2(4)

EF = 8

**** Check ****

EG = EF + FG

EF = 2x

EG = 4x

FG = 8

4x = 2x + 8

x = 4

4(4) = 2(4) + 8

16 = 8 + 8

16 = 16

4 0

3 years ago

Determine the slope and the y-intercept 6y+x=6 Answer:

pishuonlain [190]

I think y=0 because 6 multiple by 0 is 0 then x= 6 hope this helps might want to check my work to

6 0

2 years ago

Read 2 more answers

Given f(x)=x^2+5 and g(x)=2x^3-1 find (f/g)(-3)

AlekseyPX

For this case we have the following functions:

$f (x) = x ^ 2 + 5\\g (x) = 2x ^ 3-1$

By definition of composition of functions we have:

$(f / g) (x) = \frac {f (x)} {g (x)}$

Then substituting:

$f (-3) = (- 3) ^ 2 + 5 = 9 + 5 = 14\\g (-3) = 2 (-3) ^ 3-1 = 2 (-27) -1 = -54-1 = -55$

So:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

Answer:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

7 0

2 years ago

uranmaximum [27]

Answer:

ok....let me try .....

ohhhh leave it. gu

<h2>..ok bro....sorry don't be angry bjhujj</h2>

6 0

2 years ago