1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Monica [59]
3 years ago
15

Will give brainliest!

Chemistry
1 answer:
ratelena [41]3 years ago
8 0
The answer is False
You might be interested in
A 170.0 g sample of an unidentified compound contains 29.84 g sodium, 67.49
GREYUIT [131]

The empirical formula : Na₂Cr₂O₇

<h3>Further explanation</h3>

Given

170 g sample contains :

29.84 g sodium, 67.49  g chromium, and 72.67 g oxygen

Required

The compound's empirical formula

Solution

mol ratio of elements :

Na : 29.84 : 23 g/mol = 1.297

Cr : 67.49 : 51,9961 g/mol = 1.297

O : 72.67 : 16 g/mol = 4.54

Divide by 1.297

Na : Cr : O = 1 : 1 : 3.5 = 2 : 2 : 7

6 0
3 years ago
A chemical ________ involves one or more reactants changing into new products.
guapka [62]
Your answer is C. Reaction
6 0
3 years ago
Read 2 more answers
Question 3:
Oliga [24]
E. Molarity of vinegar

i hope u get this i tried to figure it out hopefully im right 

good luck!

5 0
3 years ago
The power source for all electrical objects must be a what
mariarad [96]
A circuit is a closed loop that electrons can travel in. A source of electricity, such as a battery, provides electrical energy in the circuit. ... The appliance may, for example, provide light or heat or mechanical energy.
6 0
3 years ago
Methane and chlorine react to form four products: CH3Cl, CH2Cl2, CHCl3, and CCl4. At a particular temperature and pressure, 38.4
Anastasy [175]

Answer:

How many grams of CCL4 were formed? 116.9 g

How many grams of Cl2 reacted with the CH4? 243.8 g

Explanation:

First we need to know the molar mass for every element or compound in the reaction:

M_{CH_{4}}=16 g/mol\\M_{CH_{3}Cl}=50.49g/mol\\M_{CH_{2}Cl_{2}}=84.93g/mol\\M_{CHCl_{3}}=119.38g/mol\\M_{CCl_{4}}=153.82g/mol

Now we proceed to calculate the amount of moles produced, per product:

n_{CH_{4}}=2.4\\n_{CH_{3}Cl}=0.18\\n_{CH_{2}Cl_{2}}=0.55\\n_{CHCl_{3}}=0.91\\n_{CCl_{4}}=n_{CH_{4}}-(n_{CH_{3}Cl}+n_{CH_{2}Cl_{2}}+n_{CHCl_{3}})\\n_{CCl_{4}}=0.76mol\\m_{CCl_{4}}=n_{CCl_{4}}*M_{CCl_{4}}\\m_{CCl_{4}}=116.9g

To calculate the mass of chlorine we just need to make a mass balance:

m_{CH_{4}}+m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}\\m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}-m_{CH_{4}}\\m_{Cl_{2}}=243.8g

3 0
3 years ago
Other questions:
  • The reaction between sodium and oxygen ( balanced with words)
    14·1 answer
  • Of the reactions below, which one is a double-replacement reaction?
    14·1 answer
  • A sample that contains only SrCO3 and BaCO3 weighs 0.800 g. When it is dissolved in excess acid, 0.211 g car- bon dioxide is lib
    9·1 answer
  • What is the atomic number and the mass number of an atom with 11 protons and 12 neutrons?
    15·1 answer
  • The photo shows a frozen juice pop on a hot day.
    12·2 answers
  • What is the ratio? <br> A 3:1<br> B 2:1<br> C 21:7
    12·1 answer
  • KClO3 (s) KCl (s) + 02 (g)​<br><br><br>How do you balance this equation
    10·1 answer
  • Please help thank you
    9·2 answers
  • What do alkali metals react bad with
    11·2 answers
  • Complete the decay equation for N-16: <br><br>16 7 N--&gt; __+__
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!