Answer:
167,3 grams of O2 (g)
Explanation:
According to the following balanced equation:
C3H8 + 5 02 ---> 3 CO2 + 4 H20
We calculate the mass of the moles:
5 mol O2 = 16grams/mol x2x 5= 160 grams/mol
1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol
If 44 grams C3H8 react with--------- 160 grams O2
46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2
<span>Tin has a molecular weight of 118.7 That is the mass in grams of one mole. 3.50
</span><span>118.7 = 415Four hundred and fifteen grams</span>
I don’t know what to do with the answer I don’t know how you feel sorry I didn’t
<span>An enzyme is a protein that acts as a catalyst in a chemical reaction that takes place in a living thing. <em>It is true.</em></span>
Answer:
The first thing we have to do is change and state all the units so that we can use our ideal gas law equation (
).
650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.
P = 86kPa
T = 15°C + 273K = 288K
R (Gas constant) = 8.31 kj/mol
Molar mass of Ammonia (
) = (1 x 3) + (14) = 17g/mol
n (moles) = 
3.34 mol
V = ?
Rearrange the equation to solve for Volume:
Substitute the values inside:
V = 
<u>Therefore 93 L of volume is occupied by the ammonia gas.</u>
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